For alot of points answer it right pls

A 30-06 caliber hunting rifle fires a bullet of mass 0.018 kg with a velocity of 417 m/s to the right. The rifle has a mass of 6

ryzh [129]

Answer:

V=1.19m/s

Explanation:

A 30-06 caliber hunting rifle fires a bullet of mass 0.018 kg with a velocity of 417 m/s to the right. The rifle has a mass of 6.29 kg. What is the recoil speed of the rifle as the bullet leaves the rifle?

this momentum.

it has to deal with the interaction between bullet and a gun

.lets have a deep dive into the solution

momentum is the product of mass of a body and the velocity

momentum of the bullet-=momentum of the gun

mv=MV

mass of bullet=0.018kg

v=velocity of bullet

M=mass of rifle 6.29kg

V=recoil velocity of the rifle gun

0.018*417=6.29*V

V=1.19m/s

mass is the quantity of matter in a body

velocity is change in displacement per time

3 0

3 years ago

A beam of protons is directed in a straight line along the positive zz ‑direction through a region of space in which there are c

Zinaida [17]

Answer:

The magnitude is $B = \frac{450}{7.9* 10^5}$

The direction is the positive x axis

Explanation:

From the question we are told that

The electric field is E = 450 V/m in the negative y ‑direction

The speed of the proton is $v= 7.9* 10^5\ m/s$ in the positive z direction

Generally the overall force acting on the proton is mathematical represented as

$F_E = q(\vec E + \vec v * \vec B)$

Now for the beam of protons to continue un-deflected along its straight-line trajectory then $F_E =0$

So

$0 = q( E (-y) + v(z) * \vec B)$

=> $E\^y = v \^ z * \vec B$

Generally from unit vector cross product vector multiplication

$\^ z \ * \ \^ x = \^ y$

So the direction of B (magnetic field must be in the positive x -axis )

So

$E\^y = v \^ z * B\^ x$

=> $E\^y = vB ( \^ z * \^ x)$

=> $E\^y = vB ( \^y)$

=> $E = vB$

=> $B = \frac{450}{7.9* 10^5}$

=> $B = 0.0005696 \ T$

6 0

4 years ago

What is the mass of a block concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius s

valina [46]

Answer:

12 kg

Explanation:

q = 52,800 J

c = 880 J/(kg * K) Pretty sure you missed the kg here

ΔT = 5 °C = 5 K (reminder that this only applies to ΔT and not T)

q = mcΔT ⇒ m = q/(cΔT) = 52,800 J / (880 J/(kg * K) * 5 K) = 12 kg

6 0

3 years ago

Explain how momentum is transferred when a golfer hits a ball with a golf club.

melomori [17]

Momentum is transferred through the convert wich in this case is the golf club

7 0

4 years ago

Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that

elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p = 9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

7 0

4 years ago