How many significant figures are in 0.000128?

What mass of CaCl2 (in g ) should the chemist use?

solmaris [256]

The mass of the solute required is 250.25 g.

<h3>What is the mass of the solute?</h3>

We know that the number of moles of the solute can be used to obtain the mass of the solute that is required. We can now try to find the mass of the solute that is required.

Concentration of the solution = 0.350M

Volume of the solution = 6.5 L

Number of moles of the solute = 0.350M * 6.5 L

= 2.275 moles

We now have the mass of the solute as;

2.275 moles * 110 g/mol

= 250.25 g

Th measured mass of the solute that we would have to use is 250.25 g.

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Missing parts;

A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?

3 0

1 year ago

1. If a solution of sodium chloride has 22.3 g of

lina2011 [118]

We are given:

Mass of NaCl in the given solution = 22.3 grams

Volume of the given solution = 2 L

Number of Moles of NaCl:

We know that the number of moles = Given mass / Molar mass

Number of moles = 22.3 / 58.44 = 0.382 moles

Molarity of NaCl in the Given solution:

We know that Molarity of a solution = Moles of Solute / Volume of Solution(in L)

Molarity = 0.382 / 2

Molarity = 0.191 M

7 0

3 years ago

Lead (II) carbonate decomposes to give lead (II) oxide and carbon dioxide: PbCO 3 (s) PbO (s) CO 2 (g) ________ grams of lead (I

blsea [12.9K]

Answer:

We will have 7.30 grams lead(II) oxide

Explanation:

Step 1: Data given

Mass of lead (II)carbonate = 8.75 grams

Molar mass PbCO3 = 267.21 g/mol

Step 2: The balanced equation

PbCO3 (s) ⇆ PbO(s) + CO2(g)

Step 3: Calculate moles PbCO3

Moles PbCO3 = mass / molar mass

Moles PbCO3 = 8.75 grams / 267.21 g/mol

Moles PbCO3 = 0.0327 moles

Step 4: Calculate moles PbO

For 1 mol PbCO3 we'll have 1 mol PbO and 1 mol CO2

For 0.0327 moles PbCO3 we'll have 0.0327 moles PbO

Step 5: Calculate mass PbO

Mass PbO = moles PbO * molar mass PbO

Mass PbO = 0.0327 moles * 223.2 g/mol

Mass PbO = 7.30 grams

We will have 7.30 grams lead(II) oxide

7 0

4 years ago

There are two naturally occurring isotopes of bromine. 79Br has a mass of 78.9183 amu. 81Br has a mass of 80.9163 amu. Determine

Ede4ka [16]

Atomic mass of Br = 79.904
Now lets say y% is abundance of 79Br. 
Then abundance of 81Br = (100 - y) 
mass due to 79Br = 78.9183 * y/100 = 0.789183y
mass due to 81Br = 80.9163 x (100 - y)/100 = 0.809163(100 - y) 
Therfore
0.789183y+ 0.809163(100 - y) = 79.904 
0.789183y + 80.9163 - 0.809163y = 79.904 
 - 0.01998y= 79.904 - 80.9163
= - 1.0123 
y = 1.0123/0.01998 = 50.67% 
 79Br = 50.67% 
now
81Br = 100 - 50.67 = 49.33%
hope this helps

4 0

4 years ago

As an SN2 solvent for reactions like the alkylation of acetaminophen, water would be a polar selection. Water is more polar that

evablogger [386]

Answer: polar protic solvents solvate the nucleophile necessary for attack on the substrate in SN2 substitution.

Explanation:

Aprotic solvents are solvents that lack protons such as dimethyl sulphoxide (DMSO). DMSO has no exposed positive end. The positive end is buried inside the molecular structure. As a result of this, the nucleophile is not solvated. If the nucleophile is solvated, the rate of SN2 reaction will reduce drastically because the nucleophile becomes unavailable to attack the substrate. This solvation normally occur in polar protic solvents such as water because of the exposed positive end of the molecule which interacts with the nucleophile thereby reducing the rate of SN2 reaction.

4 0

3 years ago