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Taya2010 [7]
2 years ago
6

A ball of mass m falls vertically, hits the floor with a speed ui , and rebounds with a speed u f . what is the magnitude of the

impulse exerted on the ball by the floor
Physics
1 answer:
Sholpan [36]2 years ago
5 0

Answer:

Change of momentum = M (Vf - (-Vi))   where V represents the scalar speeds of the ball or

I = M (ui + uf)  and I is the impulse ΔM V = I     Force = Change in Momentum

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Explanation: To find the answer, we need to know more about the Velocity of a body.

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Answer:

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Explanation:

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What is the stopping distance at night for a passenger vehicle traveling at 50 mph?
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In attempting to pull a 1500-kg car out of a ditch, Arnold exerts a force of 300 N for three seconds, Bob exerts a force of 500
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Answer:

Bob provided the greatest impulse.

Explanation:

Given:

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Impulse = Force × TIme

Arnold provides impulse = 300 N × 3 seconds = 900 N/s

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