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1 year ago

6

A ball of mass m falls vertically, hits the floor with a speed ui , and rebounds with a speed u f . what is the magnitude of the

impulse exerted on the ball by the floor

1 answer:

Sholpan [36]1 year ago

5 0

Answer:

Change of momentum = M (Vf - (-Vi)) where V represents the scalar speeds of the ball or

I = M (ui + uf) and I is the impulse ΔM V = I Force = Change in Momentum

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Fill in the blanks.<br>In what way are speed and velocity different?

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Answer:

4.9 x 10^-19 J, 2.7 x 10^-19 J

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first wavelength, λ1 = 410 nm = 410 x 10^-9 m

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E = h c / λ

Where, h is the Plank's constant and c be the velocity of light.

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So, energy correspond to second wavelength

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2 years ago

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3 years ago

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Answer:

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2 years ago