Answer:
Change of momentum = M (Vf - (-Vi)) where V represents the scalar speeds of the ball or
I = M (ui + uf) and I is the impulse ΔM V = I Force = Change in Momentum
m
Explanation:
Practically yes
So
If mass is more output may come less so it affects the efficiency practically
But thepritically it doesn't
i think its c
trust me