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nevsk [136]
3 years ago
14

Balance the equation​

Physics
1 answer:
mote1985 [20]3 years ago
7 0
Is this a chemistry question ?
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a hotgas is injected into at engine at 573 k and exhausts at 343 k. what is the highest efficiency of thisengine?
Dovator [93]

Answer:

230k

Explanation:

energy capacity maximum is 573 total available. 343k of that energy is present at release and subsequent loss leaving max used energy of 230k.

4 0
3 years ago
You're using a wedge to split a log. you are hitting the wedge with a large hammer to drive it into the log. it takes a force of
KIM [24]
The work performed on an object is the force multiplied by the distance it is moved, provided the movement is parallel to the force.  Since that is the case here, we can get the work by W=Fd=1900N x 0.23m = 437J.  This energy is used to split the wood.
6 0
3 years ago
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honor physics The velocity of a 200 kg object is changed from 5 m/s to 25 m/s in 50 seconds by an applied constant force. a. Wha
Ksivusya [100]

Answer:

(a) 4000 kgm/s.

(b) 80 N

Explanation:

(a) Change in momentum: This can be defined as the product of the mass of a body and its change in velocity. The S.I unit of impulse is Ns or kgm/s

Mathematically, Change in momentum is expressed as

ΔM = mΔv ..................................... Equation 1

Where ΔM = change in momentum, m = mass of the object, Δv = change in velocity = v₂ - v₁

Given: m = 200 kg, Δv = v₂ - v₁ = 25-5 = 20 m/s.

Substituting into equation 1

ΔM = 200(20)

ΔM = 4000 kgm/s.

Hence the change in momentum = 4000 kgm/s

(b)

Force: This can be defined as the ratio of the change in momentum of a body to the time required for the change.

F = ΔM/t.............................. Equation 2

Where F = force, ΔM = change in momentum, t = time.

Given: ΔM  = 4000 kgm/s, t = 50 second.

Substituting into equation 2

F = 4000/50

F = 80 N.

Hence the force  = 80 N

7 0
3 years ago
You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten
charle [14.2K]

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

\mu = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}

So

f\propto \sqrt{\dfrac{1}{\mu}}

\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m

The mass density of the E string is 0.000507 kg/m

8 0
3 years ago
Electromagnetic waves can travel through a vacuum. true or false
torisob [31]

Answer:

false

Explanation:

5 0
3 years ago
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