Answer:
The vehicle travels 56.25 metres in the interval during which body decelerates .
Explanation:
- Initial velocity of vehicle, u = 32 m/s
- Final velocity of vehicle, v = 22 m/s
- Rate of acceleration, a = - 4.8 m/
Let the distance travelled be s .
We have to determine the distance travelled by the vehicle during this time.
The equation of motion is given by
s =
<u>s = 56.25 metres</u>
The vehicle travels 56.25 metres in the interval during which body decelerates .
Answer:
0.737 m/s²
Explanation:
Given:
v₀ = 0 m/s
v = 8.20 m/s
Δx = 45.6 m
Find: a
v² = v₀² + 2aΔx
(8.20 m/s)² = (0 m/s)² + 2a (45.6 m)
a = 0.737 m/s²
This problem can be solved by using the Archimedes Principle. The principle basically lets us derive a force balance between the weight of the log and the buoyant force exerted by the water, that is
weight of log = buoyant force exerted by water
simplification of the derviation would yield,
Dl/Dw = fraction of the of the log submerged in water = (1-0.25) = 0.75
where Dl = density of the log
Dw = density of the water (1000 kg/m3)
therefore Dl = 750 kg/m^3
Hope this helps