3 years ago

Yes or no

Physics

1 answer:

Tju [1.3M]3 years ago

8 0

Answer:

1. No, it is a colloid

2. Yes

Explanation:

You might be interested in

Two identical small charged spheres are a certain distance apart, and each initially experiences an electrostatic force of magni

sweet-ann [11.9K]

Answer:

d) 1/4 F

Explanation:

The magnitude of electrostatic force between stationary charges is described by Coulomb's law. This law states that this force is proportional to the magnitudes of the charges:

$F\propto q_1q_2$

When each of the spheres has lost half its initial charge, we have:

$q_1'=\frac{q_1}{2}\\q_2'=\frac{q_2}{2}$

So, the new electrostatic force is:

$F'\propto q_1'q_2'\\F'\propto \frac{q_1}{2}\frac{q_2}{2}\\F'\propto \frac{q_1q_2}{4}\\F'\propto\frac{1}{4}F$

5 0

3 years ago

A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth. What multiple of Earth's radius RE g

Anna35 [415]

Answer:

a) $r_1=1.36R$

b) $r_2=2.083R$

Explanation:

<u>Given:</u>

a) when the initial velocity of the projectile is 0.520 times the escape velocity from the earth.

Let r be the radial distance from the earth's surface Let M be the mass of the Earth and R be the radius of the Earth

Now using conservation of Energy at earths surface and at distance r we have

$\dfrac{-GMm}{R}+\dfrac{m(0.52V_e)^2}{2}=\dfrac{-GMm}{r_1}\\\dfrac{-GMm}{R}+\dfrac{m\times 0.52^2\times \dfrac{2GM}{R}}{2}=\dfrac{-GMm}{r_1}\\r_2=1.36\ R$

b) when the Initial kinetic Energy of the projectile is 0.52 times the Kinetic Energy required to escape the Earth

Conservation of Energy we have

$\dfrac{-GMm}{R}+0.52\times KE_{escape}=\dfrac{-GMm}{r_2}\\\dfrac{-GMm}{R}+0.52\times\dfrac{m\times \dfrac{2GM}{R}}{2}=\dfrac{-GMm}{r_2}\\r_2=2.083\ R$