Answer:
n = 0.1624 moles
Explanation:
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1 answer:
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Answer: The percent yield of zinc carbonate is 5.91 %
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and
is the excess reagent.
According to stoichiometry :
1 mole of produce = 1 mole of
Thus 1.7 moles of will produce=
of
Theoretical yield of
percentage yield =
Answer:
Major organic products are- (a) propan-1-ol and (b) 2-methylpropan-2-ol
Explanation:
methyl magnesium bromide gives nucleophilic addition reaction with carbonyl group. Because methyl magnesium bromide is a strong nucleophile and carbonyl group is a strong electrophilic center.
Propanal contains an aldehyde group and propanone contains a ketone group. hence they both give nucleophilic addition with methyl magnesium bromide.
Dilute acid is added to protonate the alkoxide produced during nucleophilic addition.
Reactions are shown below.
Answer:
34.7mL
Explanation:
First we have to convert our grams of Zinc to moles of zinc so we can relate that number to our chemical equation.
So: 6.25g Zn x (1 mol / 65.39 g) = 0.0956 mol Zn
All that was done above was multiplying the grams of zinc by the reciprocal of zincs molar mass so our units would cancel and leave us with moles of zinc.
So now we need to go to HCl!
To do that we multiply by the molar coefficients in the chemical equation:
This leaves us with 2(0.0956) = 0.1912 mol HCl
Now we use the relationship M= moles / volume , to calculate our volume
Rearranging we get that V = moles / M
Now we plug in: V = 0.1912 mol HCl / 5.50 M HCl
V= 0.0347 L
To change this to milliliters we multiply by 1000 so:
34.7 mL