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babunello [35]
3 years ago
10

A 1500 kg truck travelling north at 60 km/hr collides with a 1200 kg car moving east at 15km/hr. If the two cars remain locked t

ogether after impact, with what velocity do they move immediately after the collision.​
Physics
1 answer:
Alenkinab [10]3 years ago
6 0

Answer:

33.33j+6.67i km/hr

Explanation:

From the law of conservation of momentum,

Applying,

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the truck, m' = mass of the car, u = initial velocity of the truck, u' = initial velocity of the car, V = Final velocity.

Note: let j represent the north, and i  represent the east

From the question,

Given: m = 1500 kg, u = 60j, m' = 1200 kg, u' = 15i

Substitute these values into equation 1

1500*60j+1200*15i = V(1500+1200)

90000j+18000i = 2700V

V = (90000j+18000i)/2700

V = 33.33j+6.67i km/hr

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A motorcycle has 100,000 J of kinetic energy and is traveling at 20 m/s. Find its mass.
tankabanditka [31]

Answer:

<h3>The answer is 500 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{2KE}{ {v}^{2} }  \\

v is the velocity

KE is the kinetic energy

From the question we have

m =  \frac{2 \times 100000}{  {20}^{2}  }  =  \frac{200000 }{400} =   \frac{2000}{4}  \\

We have the final answer as

<h3>500 kg</h3>

Hope this helps you

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 You are at an office party, a holiday party, or a gathering of friends at the home of a neighbor and you are engaged in convers
irina [24]

The correct answer is; Yes, you can be unconsciously eavesdropping.

Further Explanation:

When this occurs it is called the “The Cocktail Party Phenomenon.” Your mind can focus on one conversation that is being made and drown out all other speech and things going on around you. This makes your brain have auditory attention on one specific conversation.

The sensory hearing in the person listening to the conversation is subconsciously filtering the conversation into its own stream in the brain. This phenomenon can also detect certain words that are important to the person with a large amount of noise in the background.

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Learn more about the Cocktail Party Phenomenon at brainly.com/question/14532863

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3 0
3 years ago
A 40.0 -kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 13
salantis [7]

The work done by the applied force = 650 J

Given the mass of the box = 40 kg

The displacement of the box on applying force = 5 m

Applied horizontal force = 130 N

The co-efficient of friction between box and floor is = 0.3

We have to find the work done by the applied force.

Work done by the applied force = Applied Force x Displacement of the box

                                                      = 130 N x 5 m

                                                      = 650 J

[Here the unit Nm is known as Joule(J) ]

We have the co-efficient of friction. So,

The force applied due to friction = Mass of the box x Co-efficient of friction                                                                   x Acceleration due to gravity

                                                      = 40 kg x 0.3 x 9.8

                                                      = 117.6 N

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1 year ago
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