A 1500 kg truck travelling north at 60 km/hr collides with a 1200 kg car moving east at 15km/hr. If the two cars remain locked t
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Answer:
The same amount of energy is required to either stretch or compress the spring.
Explanation:
The amount of energy required to stretch or compress a spring is equal to the elastic potential energy stored by the spring:
where
k is the spring constant
is the stretch/compression of the spring
In the first case, the spring is stretched from x=0 to x=d, so
and the amount of energy required is
In the second case, the spring is compressed from x=0 to x=-d, so
and the amount of energy required is
so we see that the amount of energy required is the same.
First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
the angular speed is
And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
the angular speed is
And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion: