Two piston hydraulic problems

What is the wavelength of a 1200 Hz sound wave?

blagie [28]

Answer:

50cm

Explanation:

im honestly guessing

3 0

3 years ago

g In a cold rolling operation, steel sheets that are initially 300 cm long X 80 cm wide X 8 cm thick are cold worked to 80 cm wi

seropon [69]

Answer:

100% cold working performed on this steel

Explanation:

Using the constant volume assumption:

L₀W₀t₀ (initial) = Lₐ Wₐ tₐ (final)

thus 300 cm long X 80 cm wide X 8 cm thick = Lₐ x 80 cm wide X 5 cm thick

Lₐ = 300 cm long X 80 cm wide X 8 cm thick/80 cm wide X 5 cm thick

=480 cm

% cold working performed on this steel = Lₐ Wₐ tₐ (final) / L₀W₀t₀ (initial) 8 100

= 480 x 80 x 5/ 300 x 80 x 8 *100 = 100%

6 0

3 years ago

1. What conditions must be met for information to be considered true science?

olga55 [171]

Scientific law are proven scientific fact a theory isn’t it could be if you provide details of how it is a fact with investigations and observations,data and etc

3 0

3 years ago

A stream of doubly ionized particles (2 protons) moves at a velocity of 3.0 × 104 m/s perpendicularly to a magnetic field of 0.0

max2010maxim [7]

The force on a charged particle on a magnetic field is given by:

$F=Bqv\sin\theta$

where B is the magnitude of the field, q is the charge of the particle, v is its velocity and θ is the angle between the field and the velocity of the particle.

In this case we have that:

• The magnitude of the field is 0.09 T.

,

• The charge of the particle is 3.2 x 10 –19C .

,

• The velocity is  3.0 × 10 4 m/s

,

• The angle between the field and the velocity is 90°, since they are perpendicular.

Plugging these we have:

$\begin{gathered} F=(0.09)(3.2\times10^{-19})(3\times10^4)\sin90 \\ F=8.64\times10^{-16}\text{ N} \end{gathered}$

Therefore, the force on the charge is:

$F=8.64\times10^{-16}\text{N}$

3 0

2 years ago

A block of mass m=16.8 kg is sliding on a surface with initial velocity v=23.2 m/s. The block has a coefficient of kinetic frict

Firdavs [7]

Answer:

t = 23.92 s

Explanation:

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration (m/s²)

We define the x-axis in the direction parallel to the movement of the block and the y-axis in the direction perpendicular to it.

Forces acting on the block

W: Weight of the block : In vertical direction, downward

FN : Normal force : perpendicular to the floor, upward

fk : Kinetic friction force: parallel to the floor and opposite to the movement

F = 86.4 N , in the direction of the motion

Calculated of the W

W= m*g

W= 16.8 kg* 9.8 m/s² = 164.64 N

Calculated of the FN

We apply the formula (1)

∑Fy = m*ay ay = 0

FN - W = 0

FN = W

FN = 164.64 N

Calculated of the fk

fk = μk*FN

fk = 0.426* 164.64 N

fk = 70.13 N

We apply the formula (1) to calculated acceleration of the block:

∑Fx = m*ax , ax= a : acceleration of the block

F - fk = m*a

86.4 -70.13 = (16.8)*(-a)

16.26 = (16.8)*(-a)

a = -(16.26 )/ (16.8)

a = - 0.97 m/s²

Kinematics of the block

Because the block moves with uniformly accelerated movement we apply the following formula :

vf = v₀ + a*t Formula (2)

Where:

t: time interval (m)

v₀: initial speed (m/s)

vf: final speed (m/s)

Data:

v₀ = 23.2 m/s

vf = 0

a = -0.97 m/s²

Time it takes for the block to stop

We replace data in the formula (2) to calculate the time

vf= v₀+a*t

0 = 23.2+( -0.97)*t

(0.97)*t = 23.2

t = 23.2 / (0.97)

t = 23.92 s

7 0

3 years ago