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dimulka [17.4K]
4 years ago
5

In one experiment, a student rolls a 2 kg ball such that it collides with a wall with a force of 10,000 N. In a second experimen

t, the student rolls a 5 kg ball such that it collides with the wall at a force of 5000 N. In both experiments, the balls bounce back from the wall and eventually come to rest. Which of the following statements is true regarding the force that the wall exerts on each ball?
a. The wall exerts the same force on both balls since they both bounce back from the same wall in both experiments.
b. The wall exerts a greater force on the 5 kg ball than on the 2 kg ball since a greater force is required to cause the heavier ball to bounce back from the wall.
c. The wall exerts a greater force on the 2 kg ball than on the 5 kg ball since the force from the wall on each ball is equal to the force that each ball exerts on the wall.
d. The answer cannot be determined without knowing the distance each ball rolls before coming to rest.
Physics
1 answer:
Brums [2.3K]4 years ago
8 0

Answer:

(c) The wall exerts a greater force on the 2 kg ball than on the 5 kg ball since the force from the wall on each ball is equal to the force that each ball exerts on the wall.

Explanation:

According to Newton's third law of motion,"action and reaction are equal and opposite".

If a 2 kg ball exerts a force of 10,000 N on a wall, the wall will also exert a force of 10,000 N on the 2 kg ball but in opposite direction.

Similarly, If a 5 kg ball exerts a force of 5,000 N on a wall, the wall will also exert a force of 5,000 N on the 5 kg ball but in opposite direction.

Regardless of mass of the ball, the wall will exert equal force with which the ball collide with it.

Therefore, the wall exerts a greater force on the 2 kg ball than on the 5 kg ball since the force from the wall on each ball is equal to the force that each ball exerts on the wall.

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adelina 88 [10]

Answer

given,

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at an angle of 29◦

from the data

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V = V_x \hat{i} + V_y\hat{j}

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the magnitude of velocity

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V = 703.59 m/s

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4 years ago
A ship leaves a port at noon and travels due west at 20 knots. At 6 PM, a second ship leaves the same port and travels northwest
Amanda [17]

Answer:

v = 12.44 Knots

Explanation:

First ship starts at Noon with speed 20 Knots towards West

now we know that 2nd ship starts at 6 PM with speed 15 Knots towards North West

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now we can find the distance between two ships as

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now we have

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here we know that

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2(187.5) v = 401.44(6) + 2256

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Answer:

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3 years ago
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lora16 [44]

Answer:

hi

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