In one experiment, a student rolls a 2 kg ball such that it collides with a wall with a force of 10,000 N. In a second experimen
1 answer:
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Answer:
(a) ΔP=0.0245 kPa
(b) P=9.14 kPa
(c)ΔP=0.0245 kPa
Explanation:
(a) As it is perfect gas we can use
(P₁V₁)/T₁=(P₂V₂)/T₂
Since this constant volume so
P₁/T₁=P₂/T₂
T₂ is change in temperature
T₂=1.00+273.16
T₂=274.16 K
ΔP=6.71449-6.69
ΔP=0.0245 kPa
(b) As
(c) Same steps as in part (a)
ΔP=9.164-9.14
ΔP=0.0245kPa
Answer:
a) 24.33 m of distance.
b) 34.55° east of the south.
Explanation:
The question is incomplete. The whole exercise is the following:
<em>"Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0° west of north. Jane walks 12.0 m in a direction 30.0° south of west. They then stop and turn to face each other. </em>
<em>(a) What is the distance between them? </em>
<em>(b) In what direction should Ricardo walk to go directly toward Jane?</em><em>"</em>
Now that we know what we need to do in this question, let's head for every part of the problem.
<u>a) Distance between Ricardo and Jane</u>
In this case, we need to analyze the given data:
Ricardo (which we will call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 12 m at 30° south of west. So the distance between them, will be the point where they both stop and face each other. This point can be seen in the image attached (See picture).
Let's call the distance between them as "D", to get the distance of D, according to the picture will be:
D = J - R (1)
However, as they are facing in different angles and directions, we cannot do the difference of their values distance just like that. In order to do that, we need to calculate the components in the "x" and "y" axis of each vector. In that way, we can get the components of x and y of the Distance D, and then, the whole distance between them will be:
D = √Dx² + Dy² (2)
So, let's get the components of x and y of R and J.
For Ricardo (R):
Rx = R sin60° = 28 sin60° = -24.25 m
Ry = R cos60° = 28 cos60° = 14 m
The sign "-" it's because R it's on the second quadrant, therefore in x, we'll have to add the negative.
For Jane (J):
Jx = J cos30° = 12 cos30° = -10.39 m
Jy = J sin30° = 12 sin30° = -6 m
Again, the negative is added because J is on the third quadrant.
Now that we have the components, let's calculate vector D using expression (1):
Dx = -10.39 - (-24.25) = 13.86 m
Dy = -6 - 14 = -20 m
Now, using expression (2) we can finally know the distance between Jane And Ricardo:
D = √(-20)² + (13.86)²
<h2>D = 24.33 m</h2>This is the distance between Jane and Ricardo.
b) Direction of Ricardo walking to Jane
In this case, we already have the components of x and y of the distance between them, so, to know the direction:
Tanα = Dy/Dx
α = tan⁻¹ (Dy/Dx)
Replacing the values we have:
α = tan⁻¹ (-20/13.86)
α = 55.45°
Which should south of east or:
β = 90 - 55.45
<h2>β = 34.55°</h2>Ricardo should walk 34.55° east of south
Hope this helps
