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3 years ago

Match these items :))))))

Chemistry

1 answer:

Phoenix [80]3 years ago

3 0

1. Evaporation, 2. Reactants, 3. Gamma rays, 4. Rusting, 5. 0 degrees c, 6. Oxidation, 7. Nuclear, 8. Fusion, 9. Burning, 10. Thermo.

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What is formula for chromium (III) phosphate trihydrate and cobalt (II) phosphate octahydrate

jolli1 [7]

The formula for chromium (III) phosphate trihydrate is CrPO4- 3H20. This compound if in the anhydrous state, exists as a green crystal whereas a hydrated form violet crystal. The formula for cobalt(II) phosphate octahydrate is Co3(PO4)2•8H2O.

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3 years ago

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One theory that has been proposed about the information of the universe.

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The big bang theory is one of the multipl about the universe

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3 years ago

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A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. Calculate the empirical formula of the

IgorC [24]

Answer: The empirical formula for the given compound is $Cr_2S_3$

Explanation : Given,

Mass of product = 0.963 g

Mass of Cr = 0.500 g

Mass of S = 0.963 g - 0.500 g = 0.463 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Cr = $\frac{\text{Given mass of Cr}}{\text{Molar mass of Cr}}=\frac{0.500g}{52g/mole}=0.00962moles$

Moles of S = $\frac{\text{Given mass of S}}{\text{Molar mass of S}}=\frac{0.463g}{32g/mole}=0.0145moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00962 moles.

For Cr = $\frac{0.00962}{0.00962}=1$

For S = $\frac{0.0145}{0.00962}=1.5$

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of Cr : S = 1 : 1.5

The ratio of Cr : S = 2 : 3

Step 3: Taking the mole ratio as their subscripts.

The ratio of Cr : S = 2 : 3

Hence, the empirical formula for the given compound is $Cr_2S_3$

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4 years ago

A chemistry student answered 81 questions correctly on a 90-question test. What

nika2105 [10]

Answer:

90%

Explanation:

it will be 81/90 ×100/1

81 over 90 × 100 over 1

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3 years ago

If 3.50 moles of sodium chloride is added to your food, how many grams is added?

Ksenya-84 [330]

Answer:

204.8g

Explanation:

The number of moles of a substance is related to its mass and molecular mass as follows:

mole (n) = mass (m) ÷ molar mass (MM)

According to this question, 3.50 moles of sodium chloride (NaCl) is added to a food.

Molar mass of NaCl = 23 + 35.5

= 58.5g/mol

Using mole = mass/molar mass

Mass = molar mass × mole

Mass = 58.5g/mol × 3.5mol

Mass = 204.75

Mass = 204.8grams.

Therefore, 204.8grams of NaCl or common salt was added to the food.

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3 years ago