A 18-ft thick clay layer in the field (drained on one side) is normally consolidated. When the pressure is increase from 0.75 to
1 answer:
Answer:
a) 294.34 days
b) Δh = 25.361 cm
Explanation:
Given data:
Thickness of clay layer = 18 ft
initial pressure = 0.75 ton/ft^2
final pressure = 1.5 ton/ft^2
Δp = 0.75 ton/ft^2
eo = 1.12
e1 = 0.98
k = 4.3 * 10^-7 cm/sec
A ) determine how long it will take to reach 70% consolidation
attached below is the detailed solution
T( time in days ) = 294.34 days
B) determine settlement at 70%
attached below is the detailed solution
Δh = 25.361 cm
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Answer:
Head loss is 1.64
Explanation:
Given data:
Length (L) = 200 m
Discharge (Q) = 0.16 m3/s
According to table of nominal pipe size , for schedule 80 , NPS 14, pipe has diameter (D)= 12.5 in or 31.8 cm 0.318 m
We know,
where, f = Darcy friction factor
V = flow velocity
g = acceleration due to gravity
We know, flow rate Q = A x V
solving for V
obtained Darcy friction factor
calculate Reynold number (Re) ,
where, = density of water
= Dynamic viscosity of water at 15 degree C = 0.001 Ns/m2
so reynold number is
= 6.4 x 10^5
For Schedule 80 PVC pipes , roughness (e) is 0.0015 mm
Relative roughness (e/D) = 0.0015 / 318 = 0.00005
from Moody diagram, for Re = 640000 and e/D = 0.00005 , Darcy friction factor , f = 0.0126
Therefore head loss is
HL = 1.64 m
Answer:
Explanation:
Let assume that heating and boiling process occurs under an athmospheric pressure of 101.325 kPa. The heat needed to boil water is:
The heat liberated by the LP gas is:
A kilogram of LP gas has a minimum combustion power of . Then, the required mass is: