Answer:
a) 294.34 days
b) Δh = 25.361 cm
Explanation:
Given data:
Thickness of clay layer = 18 ft
initial pressure = 0.75 ton/ft^2
final pressure = 1.5 ton/ft^2
Δp = 0.75 ton/ft^2
eo = 1.12
e1 = 0.98
k = 4.3 * 10^-7 cm/sec
A ) determine how long it will take to reach 70% consolidation
attached below is the detailed solution
T( time in days ) = 294.34 days
B) determine settlement at 70%
attached below is the detailed solution
Δh = 25.361 cm
Answer:
hello your question is incomplete attached below is the complete question
answer : attached below
Explanation:
let ; x(t) be a real value signal for x ( jw ) = 0 , |w| > 200
g(t) = x ( t ) sin ( 2000
next we apply Fourier transform
attached below is the remaining part of the solution
The current IDS is greater than 0 since the VGS has induced an inversion layer and the transistor is operating in the saturation region.
<u>Explanation:</u>
complete question
A certain amplifier has an open-circuit voltage gain of unity, an input resistance of 1 \mathrm{M} \Omega1MΩ and an output resistance of 100 \Omega100Ω The signal source has an internal voltage of 5 V rms and an internal resistance of 100 \mathrm{k} \Omega.100kΩ. The load resistance is 50 \Omega.50Ω. If the signal source is connected to the amplifier input terminals and the load is connected to the output terminals, find the voltage across the load and the power delivered to the load. Next, consider connecting the load directly across the signal source without the amplifier, and again find the load voltage and power. Compare the results. What do you conclude about the usefulness of a unity-gain amplifier in delivering signal power to a load?
Answer:
3.03 V 0.184 W
2.499 mV 125*10^-9 W
Explanation:
First, apply voltage-divider principle to the input circuit: 1
*5
= 4.545 V
The voltage produced by the voltage-controlled source is:
A_voc*V_i = 4.545 V
We can find voltage across the load, again by using voltage-divider principle:
V_o = A_voc*V_i*(R_o/R_l+R_o)
= 4.545*(100/100+50)
= 3.03 V
Now we can determine delivered power:
P_L = V_o^2/R_L
= 0.184 W
Apply voltage-divider principle to the circuit:
V_o = (R_o/R_o+R_s)*V_s
= 50/50+100*10^3*5
= 2.499 mV
Now we can determine delivered power:
P_l = V_o^2/R_l
= 125*10^-9 W
Delivered power to the load is significantly higher in case when we used amplifier, so a unity gain amplifier can be useful in situation when we want to deliver more power to the load. It is the same case with the voltage, no matter that we used amplifier with voltage open-circuit gain of unity.
