Question

A piston having a diameter of 5.48 inches and a length of 9.50 in slides downward with a

Answer 1

Answer:

$V = 4.585 \times 10^{-3} ft/s$

Explanation:

surface Area is given as $= \pi dL$

here , d is diameter of piston

L is distance travelled by the piston

$a = \pi 5.48\times 9.5$

velocity of piston

$W = \mu A \frac{V}{t}$

where,

w is weight of piston, $\mu$ dynamic viscosity of fluid, t is thickness of fluid

$0.5 = 0.016 \times \frac{163.55}{12^2} \frac{V}{\frac{0.002}{12}}$

$0.5 = 109.033 V$

SOLVING FOR V

$V = 4.585 \times 10^{-3} ft/s$