The convection heat transfer coefficient for a clothed person standing in moving air is expressed as h 5 14.8V0.69 for 0.15 , V
2 answers:
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Answer:
a) 246.56 Hz
b) 203.313 Hz
c) Add more springs
Explanation:
Spring constant = 12000 N/m
mass = 5g = 5 * 10^-3 kg
damping ratio = 0.4
<u>a) Calculate Natural frequency </u>
Wn = √k/m =
= 1549.19 rad/s ≈ 246.56 Hz
<u>b) Bandwidth of instrument </u>
W / Wn =
W / Wn = 0.8246
therefore Bandwidth ( W ) = Wn * 0.8246 = 246.56 * 0.8246 = 203.313 Hz
C ) To increase the bandwidth we have to add more springs
Answer:
START
READ ID_Number
READ Item_description
READ length_of_auction_Days
READ minimum_required_bid
IF minimum_required_bid GREATER THAN 100
THEN
DISPLAY
Item Details are
Item Id : ID_Number
Item Description: Item_description
Length Action days: length_of_auction_Days
Minimum Required Bid: minimum_required_bid
END
Explanation:
Answer:
The maximum length of the specimen before the deformation was 358 mm or 0.358 m.
Explanation:
The specific deformation ε for the material is:
(1)
Where δL and L represent the elongation and initial length respectively. From the HOOK's law we also now that for a linear deformation, the deformation and the normal stress applied relation can be written as:
(2)
Where E represents the elasticity modulus. By combining equations (1) and (2) in the following form:
So by calculating ε then will be possible to find L. The normal stress σ is computing with the applied force F and the cross-sectional area A:
Then de specific defotmation:
Finally the maximum specimen lenght for a elongation 0f 0.45 mm is: