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Jlenok [28]
3 years ago
13

Review the chart of all the domesticated rabbits. The different types of rabbits are listed by their scientific names. If you we

re a
rabbit breeder, which rabbits could you breed to produce fertile offspring? Explain.
A)
All of the rabbits listed. They are all rabbits.
B)
None of these rabbits. They are all different species.
C)
Any of the cottontail rabbits They are the same species.
D)
Any of the rabbits on the same branch in the chart because that means
they are closely related.
Chemistry
1 answer:
Sophie [7]3 years ago
5 0

Answer: None of these rabbits listed. they are all different species

Explanation:

I got it right on usatestprep

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Mr Singh is cooking using wo pans of oiling water. Both pans are made of steel, but one pan has a much thicker base than the oth
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Answer:

See explanation

Explanation:

When either pan is heated, energy is transferred via conduction. Conduction is the process by which heat is transferred through a material, the average position of the particles remaining the same.

When the pans are heated, the particles in each pan vibrate faster and transfer this energy rapidly to neighboring particles.

The pan with a thicker base has more particles in it than the pan with lighter weight base. Note that, The rate of heat transfer is inversely proportional to the thickness of the material in question. Hence, the thicker the base, the more the number of particles present and the longer the time it takes for the food to cook.

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How many moles do you have in 37.3 g of Co(CrO4)3​
shutvik [7]

Answer:

0.0917 mol Co(CrO₄)₃

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

37.3 g Co(CrO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Co - 58.93 g/mol

Molar Mass of Cr - 52.00 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Co(CrO₄)₃ - 58.93 + 3(52.00) + 12(16.00) = 406.93 g/mol

<u>Step 3: Convert</u>

<u />37.3 \ g \ Co(CrO_4)_3(\frac{1 \ mol \ Co(CrO_4)_3}{406.93 \ g \ Co(CrO_4)_3} ) = 0.091662 mol Co(CrO₄)₃

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.091662 mol Co(CrO₄)₃ ≈ 0.0917 mol Co(CrO₄)₃

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