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natulia [17]
3 years ago
9

How many grams of oxygen would be produced by the electrolysis of 72.0 grams of water ? 2H2O--> O2+2H2 (Must be made to fit i

nto the chart underneath #8)

Chemistry
1 answer:
astraxan [27]3 years ago
8 0
Molar mass H₂O = 18.0 g/mol   and O₂ = 32.0 g/mol

2 H₂O --------> O₂ + H₂

(2* 18.0 g ) H₂O ---------->  32 g O₂
72.0 g H₂O ----------------> ?

mass of O₂ = 72.0 * 32 / 36

mass of O₂ = 2304 / 36

= 64 g of O₂

hope this helps!
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The final temperature is -138 °C.

Explanation:

Using the equation of specific heat

Q = m*c* del T

We can easily find the final temperature of a 73.174 g of copper sample. As we know that specific heat is the amount of energy required to raise the temperature of the object to 1°C.

The specific heat of copper is known as 0.387 J/g°C and the initial temperature is said as 102 °C . The mass is given as 73.174 g. The heat released is 6800 J.

Since the heat is released the Q value will be negative.

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T_{final}-102=\frac{-6800}{0.387*73.174} =-240

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Explanation:

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Change in temperature = Final temp - initial temp

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