How many grams of oxygen would be produced by the electrolysis of 72.0 grams of water ? 2H2O--> O2+2H2 (Must be made to fit i
nto the chart underneath #8)
1 answer:
Molar mass H₂O = 18.0 g/mol and O₂ = 32.0 g/mol
2 H₂O --------> O₂ + H₂
(2* 18.0 g ) H₂O ----------> 32 g O₂
72.0 g H₂O ----------------> ?
mass of O₂ = 72.0 * 32 / 36
mass of O₂ = 2304 / 36
= 64 g of O₂
hope this helps!
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