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Furkat [3]
3 years ago
7

How can resonance overcome damping of an oscillating system? ​

Physics
1 answer:
Aneli [31]3 years ago
6 0

Answer:

When one system vibrating at its natural frequency is put closer to a stationary system, the stationary system receives impulses.

At resonant frequency, the system vibrating at its own natural frequency suddenly goes on decreasing in order to cope with neighboring system.

These decrease in frequency is known as damping.

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When measuring the diameter of a cylinder the following measurements are obtained.
Arlecino [84]

Answer:

a. 1.80 %

b. 0.60 %

c. 1.20 %

d. 0.60 %

e. 0.60 %

Explanation:

In order to calculate percent uncertainties in each case, we forst need to calculate the average value:

Average Diameter = (16.4 mm + 16.8 mm + 16.9 mm + 16.6 mm +16.8 mm)/5

Average Diameter = 16.7 mm

Now, the formula for percent uncertainty is:

% Uncertainty = (Uncertainty/Average) * 100 %

where,

Uncertainty = |Value - Average|

For Each Case:

<u>a. 16.4 mm</u>:

Uncertainty = |16.4 mm - 16.7 mm| = 0.3 mm

Therefore,

% Uncertainty = (0.3 mm/16.7 mm) * 100%

<u>% Uncertainty = 1.80 %</u>

<u></u>

<u>b. 16.8 mm</u>:

Uncertainty = |16.8 mm - 16.7 mm| = 0.1 mm

Therefore,

% Uncertainty = (0.1 mm/16.7 mm) * 100%

<u>% Uncertainty = 0.60 %</u>

<u></u>

<u>c. 16.4 mm</u>:

Uncertainty = |16.9 mm - 16.7 mm| = 0.2 mm

Therefore,

% Uncertainty = (0.2 mm/16.7 mm) * 100%

<u>% Uncertainty = 1.20 %</u>

<u></u>

<u>d. 16.6 mm</u>:

Uncertainty = |16.6 mm - 16.7 mm| = 0.1 mm

Therefore,

% Uncertainty = (0.1 mm/16.7 mm) * 100%

<u>% Uncertainty = 0.60 %</u>

<u></u>

<u>e. 16.8 mm</u>:

Uncertainty = |16.8 mm - 16.7 mm| = 0.3 mm

Therefore,

% Uncertainty = (0.1 mm/16.7 mm) * 100%

<u>% Uncertainty = 0.60 %</u>

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Uncle Harry weighs 750 N. What is his mass in kg?
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Answer:

W = MG

750 = M * 10

M = 750/10

M = 75 kg

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