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Furkat [3]
3 years ago
7

How can resonance overcome damping of an oscillating system? ​

Physics
1 answer:
Aneli [31]3 years ago
6 0

Answer:

When one system vibrating at its natural frequency is put closer to a stationary system, the stationary system receives impulses.

At resonant frequency, the system vibrating at its own natural frequency suddenly goes on decreasing in order to cope with neighboring system.

These decrease in frequency is known as damping.

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Over 4 seconds, a car's momentum decreases by 1000 kg m/s how much force did it take to make this happen?
kotykmax [81]

Answer:

250N

Explanation:

Given parameters:

Time  = 4s

Momentum  = 1000kgm/s

Unknown:

Force  = ?

Solution:

To solve this problem, we use Newton's second law of motion;

      Ft  = Momentum

F is the force

t is the time

So;

          F x 4 = 1000kgm/s

          F  = 250N

6 0
3 years ago
When popcorn is heated over a flame, the kernel burst open. why does this occur?
Bezzdna [24]
<span>If you faced the situation when  popcorn is heated over a flame and the kernel burst opened the thing which caused that is definitely : the air and water vapor which remain in the kernell have expanded.
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4 0
3 years ago
A fluid in an aquifer is 23.6 m above a reference datum, the fluid pressure (in gage pressure) is 4390 n/m2 and the flow velocit
Phoenix [80]

As per Bernuolli's Theorem total energy per unit mass is given as

\frac{P}{\rho} + \frac{1}{2}v^2 + gH = E

now from above equation

P = 4390 N/m^2

\rho = 0.999 * 10^3

v = 7.22 * 10^{-4} m/s

H = 23.6 m

now by above equation

\frac{4390}{0.999*10^3} + \frac{1}{2}*(7.22*10^{-4})^2 + 9.8*23.6 = E

E = 235.7 J/kg

Part B)

Now energy per unit weight

U = \frac{E}{g}

U = \frac{235.7}{9.8}

U = 24 m

7 0
4 years ago
Prove that s=ut+½at²​
katrin2010 [14]

Explanation:

Distance travelled = Area under the line

= ut + ½ (v-u)t

Acceleration (a) = (v-u)/t and so (v-u) = at

Therefore,

Distance travelled (s) = ut + ½ (v-u)t = ut + ½ (at)t = ut + ½ at²

Thus,proved.

3 0
3 years ago
A body of mass 2kg moves round a circle of radius 5m with a constant speed of 10m/s. Calculate the force toward the centre of th
antiseptic1488 [7]

Answer:

F = 5

Explanation:

F = m x v^2/r = 2 x 10^2/5 =200/5 = 40 (N)

5 0
3 years ago
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