Question

2Mg + O2 → 2MgO If you are burning 5.8332 g of Mg, how many grams of MgO will this make?

Answer 1

Answer:

9.6730

Explanation:

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Answer 2

Answer:

9.6724 g MgO

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Stoichiometry

• Reading a Periodic Table
• Using Dimensional Analysis

Explanation:

Step 1: Define

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 5.8332 g Mg

Step 2: Identify Conversions

[RxN] 2 mol Mg = 2 mol MgO

Molar Mass of Mg - 24.31 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol

Step 3: Stoichiometry

1. Set up:                              $\displaystyle 5.8332 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})(\frac{40.31 \ g \ MgO}{1 \ mol \ MgO})$
2. Multiply/Divide:                                                                                               $\displaystyle 9.67241 \ g \ MgO$

Step 4: Check

Follow sig fig rules and round. We are given 5 sig figs.

9.67241 g MgO ≈ 9.6724 g MgO