Answer:
39 mol AgNO3
Explanation:
We have the equation 4HNO3 + 3Ag -----> 3AgNO3 + NO + 2H2O
We want to calculate the number of silver nitrate (AgNO3) moles that would be produced from 52 moles of nitric acid ( HNO3 )
We can calculate this by using mole ratio as well as dimensional analysis.
The mole ratio of Silver nitrate to nitric acid based on the balanced equation is 3AgNO3:4HNO3.
Using this we can create a table: The table is attached.
Breakdown of the table.
The moles of nitric acid cancel out and we multiply 52 by 3/4 to get 39 moles of Silver nitrate.
The frequency of a wave represents B. the number of wave cycles that pass through a specific point within a given time.
The distance between two consecutive crests and the length of a wave are the <em>wavelength</em>.
The distance between the highest and lowest points of a wave is <em>twice the amplitude</em>.
Answer: The balanced equation for the given reaction is
.
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side.
For example, 
Here, number of atoms on reactant side are as follows.
Number of atoms on product side are as follows.
To balance this equation, multiply
by 2 on reactant side and multiply
by 2. Hence, the equation will be re-written as follows.

Here, number of atoms on reactant side are as follows.
Number of atoms on product side are as follows.
Now, there are same number of atoms on both reactant and product side. So, this equation is balanced.
Thus, we can conclude that the balanced equation for the given reaction is
.
<u>Answer:</u> The mass of phosphorus that is present for given amount of calcium is 28.53 g.
<u>Explanation:</u>
We are given:
Mass of calcium = 50 grams
The chemical formula of calcium phosphate is 
Molar mass of calcium = 40 g/mol
Molar mass of phosphorus = 31 g/mol
In 1 mole of calcium phosphate, 120 grams of calcium is combining with 62 grams of phosphorus.
So, 50 grams of calcium will combine with =
of phosphorus.
Hence, the mass of phosphorus that is present for given amount of calcium is 28.53 g.