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Maslowich
2 years ago
15

On increasing which of the following factors, decreases the extent of physisorption? Surface area of the adsorbent Critical temp

erature of the adsorbate Concentration of adsorbate Temperature at which adsorption is carried out
Chemistry
1 answer:
Citrus2011 [14]2 years ago
4 0

Answer: On increasing temperature at which adsorption is carried out decreases the extent of physisorption.

Explanation:

An adsorption where molecules of the adsorbate are placed or held on the surface of adsorbent by Vander waals forces is called physisorption.

There is basically physical bonding between the molecules of gas to the surface of a solid or liquid.

Physisorption is reversible in nature and occurs at low temperatures.

It is not specific in nature which means that all gases are adsorbed on the surface of every solid substance to some extent.

Thus, we can conclude that on increasing temperature at which adsorption is carried out decreases the extent of physisorption.

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what happens to the average kinetic energy of ideal gas molecules when the pressure of the gas is increased by reducing the volu
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Answer:

The pressure of the gas is increased by reducing the volume at constant temperature. ... The average velocity of the molecules is increased by a factor of 2.

Explanation:

4 0
2 years ago
Develop a demonstration to show how weight is not the same thing as mass
maksim [4K]

Answer with Explanation:

"Mass" and "weight" should never be used interchangeably with each other. Mass refers to the <u>total amount of matter</u><u> that can be measured in an object, </u>while weight refers to the<u> measure of the</u><u> force of gravity</u><u> that is acting on the object's mass.</u>

The mass of an object is<u> constant</u> (meaning, it doesn't change even if the object will be placed on another location) while the weight of an object relies on the <em>force of gravity.</em> So, this means that your mass on Earth and on the moon are identical, however, your weight on Earth and on the Moon are different. You will weigh lesser on the Moon because it has a lesser surface gravity than that of Earth.

So, this explains the answer.

4 0
3 years ago
Carbonic acid reacts with water to yield bicarbonate ions and hydronium ions: h2co3+h2o?hco3?+h3o+ identify the conjugate acid-b
Levart [38]
Conjugate base pairs are acid and bases having common features. These features are the equal gain or loss of protons of the pairs. Conjugate pairs should always be one base and one acid. One would not exist without the other. Conjugate acids are the substances that gains protons while conjugates bases are those that loses protons. <span>The substances in the equilibrium reaction that is given is identified as follows: 
HCO3^-      +     H2O <----->   CO3^2-          +             H3O^+ 
 acid                   base         conjugate base           conjugate acid 

HCO3^- ion is an intermediate molecule of CO2 and CO3^2-. When we add OH- to HCO3^-, we produce CO3^2-. And when we add H+ to HCO3, we produce CO2. </span>
7 0
2 years ago
are either positively charged or negatively charged species in which the number of protons and electrons are not equal. ________
fredd [130]

Answer:

1. Ions are either negatively or positively charged species in which the number of electrons and protons are not equal.

2. The chemical bond that arises due to the sharing of electrons is termed a covalent bond.

3. The positively charged ions are called cations, which comprise more protons than electrons.

4. An example of a polyatomic anion is the hydroxide anion.

5. The system of assigning an unambiguous name to a compound is called nomenclature.

6 0
2 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
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