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WITCHER [35]
3 years ago
11

Each of the following solutions is separated from a solution containing pure water with a semipermeable membrane. Assuming they

all have the same temperature, rank the solutions from the highest to the lowest osmotic pressure. Rank the solutions from highest to lowest osmotic pressure. To rank items as equivalent, overlap them: 5.0% KCl, 0.7% KCl, 1.5% KCl, 1.8% KCl, 8.6% KCl.
Chemistry
1 answer:
liberstina [14]3 years ago
3 0

Answer:

Osmotic pressure is a measure of a solution's tendency to attract or take in water from another solution when the two solutions are separated by a semipermeable membrane

The order of increasing osmotic pressure is

  1. 0.7% KCl
  2. 1.5% KCl
  3. 1.8% KCl
  4. 5.0% KCl
  5. 8.6% KCl

Explanation:

Osmotic pressure is the strength of movement of the solvent of a solution through a semipermeable membrane separating solutions of different  concentration thereby causing the solvent (such as water) to move from a region of high solute concentration to a region of lower solute concentration.

The amount of osmotic pressure through a semipermeable membrane separating solutions of different concentration is given by

π = i×M×R×T

π = osmotic pressure

i = van't Hoff's factor

(M) = molar concentration

(T) = temperature in kelvin

R = ideal gas constant (0.08206 L atm mol⁻¹K⁻¹)

As seen above , the osmotic pressure is directly proportional to the concentration of the solution thus in the order of increasing osmotic pressure we have

  1. 0.7% KCl
  2. 1.5% KCl
  3. 1.8% KCl
  4. 5.0% KCl
  5. 8.6% KCl
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Volumen = constant => P/T = constant

T1 = 21°C + 273.15 = 294.15 k
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P2 / 269.65k = 0.82atm / 294.15k

P2 = [0.82atm / 294.15k] * 269.65kg = 0.75 atm
3 0
3 years ago
How much heat in kilojoules is required to heat 56 l of water from 89 ∘f to 212 ∘f?
scoundrel [369]
You would need 67 if you add 56 and 89 = 145 and how i got 67. i went and subtract 212 and 145 = 67 and hope that answer you want if not well least i try
3 0
3 years ago
Assuming that the experiments performed in the absence of inhibitors were conducted by adding 5 μl of a 2 mg/ml enzyme stock sol
prohojiy [21]

Hey there!:

From the given data ;

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Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:

[E]t in molar  = g/L * mol/g

[E]t  = 0.01 g/L * 1 / 45,000

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Vmax = 0.758 umole/min/ per mL

= 758 mmole/L/min

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Therefore :

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Kcat = 758000 / 2.2*10⁻⁷ M

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4 0
3 years ago
(Thermodynamics)
frutty [35]

Answer:

3853 g

Step-by-step explanation:

M_r: 107.87

         16Ag + S₈ ⟶ 8Ag₂S; ΔH°f =  -31.8 kJ·mol⁻¹

1. Calculate the moles of Ag₂S

Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S

2. Calculate the moles of Ag

Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag

3. Calculate the mass of Ag

Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag

You must react 3853 g of Ag to produce 567.9 kJ of heat

3 0
3 years ago
How many moles are in 43.9 L of oxygen
Ede4ka [16]

Answer: 2 mol

Explanation:

- According to the ideal gas law, One mole of an ideal gas at STP (standard temperature and normal pressure) occupies 22.4 liters.

- Using cross multiplication,

                               1 mol of (O2)        →       22.4 L

                                       ?                   →        43.9 L

Therefore, the number of moles of oxygen in 43.9 L = (43.9 × 1)/ 22.4 = 1.96 mol≈ 2 mol..


3 0
3 years ago
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