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netineya [11]
3 years ago
7

Please help!

Chemistry
1 answer:
astraxan [27]3 years ago
8 0
D. That is the correct answer
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2.<br> An alkane has at least on C=C<br> bond.<br> ut of<br> Select one:<br> O True<br> O False
garik1379 [7]
I think it’s false?????
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sesenic [268]
2nd one is the awnser
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The expected o-c-h angle in this molecule is degrees. the expected hybridization at the central carbon is
WINSTONCH [101]

Each neutral carbon atom contains four valence electrons and may form up to four electron domains. Possible hybridizations include

  • sp^{3}, four electron domains, as in ethane \text{C}_2\text{H}_6
  • sp^{2}, three electron domains, as in ethene \text{C}_2\text{H}_4
  • sp, two electron domains, as in ethyne \text{C}_2\text{H}_2

Molecules of each of the three hybridization demonstrate spatial configurations that would maximizes the separation between the electron domains.

  • Carbon atoms with a sp^{3} hybridization would demonstrate a tetrahedral configuration with a bond angle of approximately 109.5\textdegree{}
  • Carbon atoms with a sp^{2} hybridization would demonstrate a triangular planar configuration with a bond angle of 120\textdegree{}
  • Carbon atoms with a sp hybridization would demonstrate a linear configuration with a bond angle of 180\textdegree{}

Bond angles are characteristic of the spatial configuration of electron domains and identifies the hybridization of the central carbon atom.

Note that each hydrogen atom contains only one valence electron and would form only single bonds. It takes two valence electrons for oxygen atoms to achieve an octet such that each oxygen form only two bonds at a single time. Therefore given the fact that the carbon is bonded to both hydrogen and oxygen, only the following hybridizations are possible

  • sp^{3} in which the oxygen atom forms a carbon-oxygen double bond with the central carbon atom;
  • sp^{2} in which the oxygen atom forms a single bond with the central carbon atom and with a second atom.
3 0
3 years ago
The pK of acetic acid is pK = 4.76. For a 0.1 M solution of acetic acid at a pH = 4.76 what is the concentration of [H+]?
spin [16.1K]

Answer:

[H+] = 1.74 x 10⁻⁵

Explanation:

By definition pH = -log  [H+]

Therefore, given the pH,  all we have to do is  solve algebraically for  [H+] :

[H+]  = antilog ( -pH ) =  10^-4.76 = 1.74 x 10⁻⁵

6 0
3 years ago
Distinguish between sugar and non-sugar with examples.
kap26 [50]

Answer:

Reducing sugars are sugars where the anomeric carbon has an OH group attached that can reduce other compounds. Non-reducing sugars do not have an OH group attached to the anomeric carbon so they cannot reduce other compounds. ... Maltose and lactose are reducing sugars, while sucrose is a non-reducing sugar

3 0
3 years ago
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