Answer:
1.242 g/mL
Explanation:
Step 1: Given data
Mass of the empty container (m₁): 80.21 g
Mass of the filled container (m₂): 105.22 g
Volume of the unknown liquid (V): 20.14 mL
Step 2: Calculate the mass of the liquid
The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.
Step 3: Calculate the density of the unknown liquid
The density of the liquid is equal to its mass divided by its volume.
Answer: 4.45 moles of will be produced.
Explanation:
The balanced chemical equation:
As nitric acid is the excess reagent, calcium hydroxide is the limiting reagent as it limits the formation of product.
According to stoichiometry :
1 mole of produce = 2 moles of
Thus 2.27moles of will produce = of
Thus 4.45 moles of will be produced.
The Fe is our limiting reactant here. First, convert the mass of Fe given to moles of Fe by dividing mass by the molar mass:
(51.3 g Fe)/(55.845 g/mol) = 0.9186 mol Fe.
According to the balanced equation, 2 moles of Fe2O3 are produced for every 4 moles of Fe that are consumed. In other words, half as many moles of Fe2O3 will be produced as there are Fe that react:
(0.9186 mol Fe)(2 mol Fe2O3/4 mol Fe) = 0.4593 mol Fe2O3.
Finally, convert the moles of Fe2O3 back to grams by multiplying by the molar mass of Fe2O3:
(0.4593 mol Fe2O3)(159.6882 g/mol) = 73.3 g Fe2O3.
So, 73.3 grams of Fe2O3 are formed.
From another answer, it is most likely E. Horizon. Hope this helps!