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Airida [17]
3 years ago
8

when u walk your dog ur using energy from the sunlight to power this activity explain (ANSWER PLESSSSSSSSSSSSSSZZZ)

Chemistry
1 answer:
wariber [46]3 years ago
4 0

Answer:

When you walk your dog, you are using energy from the sunlight to power the activity. Explain. The energy you use is transferred from glucose, which got it directly from sunlight.

Explanation:

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How many grams of mercury would be contained in 15 compact fluorescent light bulbs?
zhenek [66]

Answer:

Grams of mercury= 0.06 g of Hg

Note: The question is incomplete. The complete question is as follows:

A compact fluorescent light bulb contains 4 mg of mercury. How many grams of mercury would be contained in 15 compact fluorescent light bulbs?

Explanation:

Since one fluorescent light bulb contains 4 mg of mercury,

15 such bulbs will contain 15 * 4 mg of mercury = 60 mg

1 mg = 0.001 g

Therefore, 60 mg = 0.001 g * 60 = 0.06 g of mercury.

Compact fluorescent lightbulbs (CFLs) are tubes containing mercury and noble gases. When electricity is passed through the bulb, electron-streams flow from a tungsten-coated coil. They collide with mercury atoms, exciting their electrons and creating flashes of ultraviolet light. A phosphor coating on the inside of the tube absorbs this UV light flashes and re-emits it as visible light. The amount of mercury in a fluorescent lamp varies from 3 to 46 mg, depending on lamp size and age.

5 0
3 years ago
Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of
Kaylis [27]

Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles

b) moles of I_2

\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles

H_2(g)+I_2(g)\rightarrow 2HI(g)

According to stoichiometry :

1 mole of I_2 require 1 mole of H_2

Thus 0.0787 moles of l_2 require=\frac{1}{1}\times 0.0787=0.0787moles of H_2

Thus l_2 is the limiting reagent as it limits the formation of product and H_2 acts as the excess reagent. (10.0-0.0787)= 9.92 moles of H_2are left unreacted.

Mass of H_2=moles\times {\text {Molar mass}}=9.92moles\times 2.01g/mol=19.9g

Thus 19.9 g of H_2 remains unreacted.

5 0
3 years ago
Use the value of the Avogadro constant (6.02 × 1023 mol–1) to calculate the total number of atoms in 7.10 g of chlorine atoms. (
kolbaska11 [484]

The total number of atoms in 7.10g of chlorine is 1.204 × 10²³atoms.

HOW TO CALCULATE NUMBER OF ATOMS:

  • The number of atoms in a substance can be calculated by multiplying the number of moles in that substance by Avogadro's number as follows:

  • no. of atoms = no. of moles × 6.02 × 10²³ mol-¹

  • The number of moles in 7.10g of Cl is calculated as follows:

no. of moles = mass ÷ molar mass

no. of moles = 7.10g ÷ 35.5g/mol

no. of moles = 0.2mol

no of atoms = 0.2mol × 6.02 × 10²³

no. of atoms = 1.204 × 10²³atoms.

  • Therefore, the total number of atoms in 7.10g of chlorine is 1.204 × 10²³atoms.

Learn more: brainly.com/question/15488332?referrer=searchResults

6 0
2 years ago
B. The highly toxic gas phosgene is produced by the reaction CO(g) + Cl2(g) COCl2(g), ΔH = –108 kJ/mol. Use this reaction to ans
galben [10]

Answer:

I. Increasing pressure will allow more frequent successful collision between particles due to the particles being closer together.

II. Rate of reaction increases due to more products being made; as increased pressure favours the exothermic side of the equilibrium.

III. Increasing temperature provides particles lots of (Kinetic) energy, for more frequent successful collision due to the particles moving at a faster rate than before. However, favouring the endothermic side of the equilibrium due to lots of energy required to break and form new bonds.

IV. Rate of reaction increases due to increase temperature favouring both directions of the equilibrium - causing products to form faster.

Hope this helps!

6 0
2 years ago
An aqueous solution of calcium hydroxide is standardized by titration with a 0.112 M solution of hydrobromic acid. If 15.2 mL of
TiliK225 [7]

Answer:

0.0457 M

Explanation:

The reaction that takes place is:

  • 2HBr + Ca(OH)₂ → CaBr₂ + 2H₂O

First we<u> calculate how many moles of acid reacted</u>, using the <em>HBr solution's concentration and volume</em>:

  • Molarity = Moles / Volume
  • Molarity * Volume = Moles
  • 0.112 M * 12.4 mL = 1.389 mmol HBr

Now we <u>convert HBr moles to Ca(OH)₂ moles</u>, using the stoichiometric ratio:

  • 1.389 mmol HBr * \frac{1mmolCa(OH)_{2}}{2mmolHBr} = 0.6944 mmol Ca(OH)₂

Finally we <u>calculate the molarity of the Ca(OH)₂ solution</u>, using the <em>given volume and calculated moles</em>:

  • 0.6944 mmol Ca(OH)₂ / 15.2 mL = 0.0457 M
7 0
3 years ago
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