Block A of 5 kg with a speed of 3 m/s collides with block B of 10 kg that is stationary. After the collision, block B travels wi
1 answer:
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Explanation:
The given data is as follows.
k = 130 N/m, = 17 cm = 0.17 m (as 1 m = 100 cm)
mass (m) = 2.8 kg
When the spring is compressed then energy stored in it is as follows.
Energy =
Now, spring energy gets converted into kinetic energy when the box is launched.
So, =
=
= 1.34
v = 1.15 m/sec
Now,
Frictional force =
=
= 4.116 N
Also, Kinetic energy = work done by friction
1.8515 =
d = 0.449 m
Thus, we can conclude that the box slides 0.449 m across the rough surface before stopping.
The kinetic energy is 
and the height of the building doesn't matter at all.
joules
Probably because of the drag coefficient and the density of the liquid.
