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NemiM [27]
3 years ago
12

Suppose a powerful battery is connected between a pair of inert graphite electrodes dipped into a pot of molten zinc chloride (s

ee sketch at right).
Chemistry
1 answer:
zvonat [6]3 years ago
3 0
The electrode A is a cathode. This is because it is negatively charged electrode and it attracts cations, or we can say it is positively charged. 
The reaction occurs at the cathode
Zn2+ +2e⇒Zn
Anode reaction is 
2CL- ⇒CL2+2e-
The overall reaction will be Zncl2(l) which completely disassociates then it is zn∧2+(l)+2cl∧-(l). 
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What is the total number of valence electrons in the dot structure of CBr4? Explain how you determined this answer. What is the
Mnenie [13.5K]

Answer:- There are 32 valence electrons and it's tetrahedral in shape.

Explanations:- Atomic number of carbon is 6 and it's electron configuration is 1s^22s^22p^2 . It has 4 electrons in the outer most shell means it has 4 valence electrons.

Atomic number of Br is 35 and it's electron configuration is 1s^22s^22p^63s^23p^64s^23d^1^04p^5 . It has 7 electrons in the outer most shell(2 in 4s and 5 in 4p) .

There is one C and four Br in the given compound. So, total number of valence electrons = 4+4(7) = 4+28 = 32

Four Br atoms are bonded to the central carbon atom and also there isn't any lone pair present on carbon. It makes it tetrahedral.

5 0
3 years ago
Another simple question and I need it bad
podryga [215]
Oh this is extremely hard...i might just die lol jk its the last one measuring cylinder :)
3 0
3 years ago
Read 2 more answers
For a particular reaction at 235.8 °C, ΔG=−936.92 kJ/mol , and ΔS=513.79 J/(mol⋅K) . Calculate ΔG for this reaction at −9.9 °C.
Rudik [331]

Answer:

-138.9 kJ/mol

Explanation:

Step 1: Convert 235.8°C to the Kelvin scale

We will use the following expression.

K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K

Step 2: Calculate the standard enthalpy of reaction (ΔH°)

We will use the following expression.

ΔG° = ΔH° - T.ΔS°

ΔH° = ΔG° / T.ΔS°

ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K

ΔH° = -3.583 kJ (for 1 mole of balanced reaction)

Step 3: Convert -9.9°C to the Kelvin scale

K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K

Step 4: Calculate ΔG° at 263.3 K

ΔG° = ΔH° - T.ΔS°

ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K

ΔG° = -138.9 kJ/mol

8 0
3 years ago
WHAT IS THE ABILITY OF A SUBSTANCE TO BE DISSOLVED
siniylev [52]

Answer:

Solubility

Explanation:

8 0
3 years ago
An unknown amount of helium (He) gas occupies 10.5 L at 1.52 atm pressure and 335 K. What is the mass of helium gas in the conta
Masteriza [31]

Answer:

The lectures in this unit cover gases. This lecture covers the Ideal Gas Law and partial pressures.

Ideal Gas Law

In our previous lecture we discovered a relationship between the pressure, volume, temperature,

and number of moles in gases. After scientists worked out the individual relationships between

pressure, volume, temperature, and the number of moles, it was clear that a single law could

bring all of these individual laws together. This unifying law is called the ideal gas law. An

ideal gas is one which follows the ideal gas law. Not all gases are perfectly ideal in this sense

but most of them are close enough to it that the law applies well.

I. Ideal Gas Law

The Ideal Gas Law unifies all these independent laws as follows:

PV = nRT

Where P = Pressure, V = Volume, T = Temperature, and n = number of moles.

The remaining value, R, is the constant which makes the rest of these factors work together

mathematically. Once the relationship between all individual factors was found it was trivial to

calculate R: it is the value of

PV

nT for any gas since they all act the same way!

There are several numerical values for R depending on which units you are using (atm or torr or

bars, L or mL, Joules (energy) etc). Our class uses this one:

R = .0821

L·atm

mole·K

The ideal gas law helps us calculate variables such as pressure, volume, temperature, or number

of moles without having to make a comparison.

For example, if 3.5 moles O2 has a volume of 27.0 L at a pressure of 1.6 atm, what is the

temperature of the sample?

Here we are given n = 3.5 moles, V = 27.0 L, P = 1.6 atm. We rearrange the ideal gas law to

solve for temperature as follows:

PV = nRT

PV

nR = T

(1.6 atm)(27.0 L)

(3.5 moles)(0.0821 L·atm/mol·K) = 150.3 K

Explanation:

4 0
3 years ago
Read 2 more answers
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