Answer:
Moles de LiOH= 0.33212 Moles
Explanation:
1 Mol of LiOH -->6.022*10^23 molecules of LiOH
therefore
![2*10^{23}~molecules ~of~LiOH=\frac{2*10^{23}}{6.02*10^{23}}Moles~of#LiOH](https://tex.z-dn.net/?f=2%2A10%5E%7B23%7D~molecules%20~of~LiOH%3D%5Cfrac%7B2%2A10%5E%7B23%7D%7D%7B6.02%2A10%5E%7B23%7D%7DMoles~of%23LiOH)
Of Uranium-235 remains after 2.8 x 10^9 years, what was the original mass of the sample of Uranium-235? The half-life of Uranium-235 is 7.0 x 10^8 years. Uranium-232 has a half life of 68.8 years.
Hello Mate!Well, there are
many definitions and descriptions of isolated systems, and
here are some of them:
1.
It can be a physical system which is located very very far from all other systems, so there is absolutely no interaction between them, thus making it isolated.
2.
It can be a thermodynamic system with rigid walls, which prevents mass and energy to pass through.
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Answer:
5.78 × 10¹⁴ Hz
Explanation:
Step 1: Given and required data
- Wavelength of this light (λ): 519. nm
- Frecquency of this light (ν): ?
- Speed of light (c): 3.00 × 10⁸ m/s
Step 2: Convert "λ" to meters
We will use the conversion factor 1 m = 10⁹ nm.
519. nm × 1 m/10⁹ nm = 5.19 × 10⁻⁷ m
Step 3: Calculate the frecquency of this light
We will use the following expression.
c = λ × ν
ν = c/λ
ν = (3.00 × 10⁸ m/s)/5.19 × 10⁻⁷ m
ν = 5.78 × 10¹⁴ s⁻¹ = 5.78 × 10¹⁴ Hz
Answer:
Volume is 0.00233mL
Explanation:
Hello,
The density of a substance is the mass per unit volume of that substance.
Density = mass / volume
To solve this question, we need to get our data first.
Data;
Density = 19.3g/mL
Mass = 45mg = 0.045g
Volume = ?
Density = mass / volume
Density (ρ) = mass (m) / volume (v)
ρ = m / v
v = m / ρ
v = 0.045 / 19.3
v = 0.00233mL
The volume of the substance is 0.00233mL