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3 years ago

7

please let me know if the answer is true or false. if false, please tell me what's false about it. the word that they are wonder

ing if it needs to be changed is highlighted

1 answer:

sveticcg [70]3 years ago

4 0

Answer:

false the answer is woody

Explanation:

those are the two types of stems

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The force that one surface exerts on another when the 2 rub against each other is called

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The friction force
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3 years ago

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Which phase change is the opposite of boiling?

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Condensation is the opposite of boiling

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3 years ago

Compare the viscosity property of solid and liquid.

Nitella [24]

Answer

There is nothing like viscosity in solid because most of the solids usually have a rigid body. This is due to strong intermolecular forces. And it is due to this strong force between the molecules that they are unable to move and they remain fixed at their position. Some solids such as graphite which have layered structure, don't possess the property of viscosity, because of the strong force between the layers.

Explanation:

Viscosity is the property of a fluid that opposes the relative motion between two surfaces of the fluid that are moving at different velocities. In simple terms, viscosity means friction between the molecules of fluid.

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3 years ago

The equilibrium constant Kc for the reaction PCl3(g) + Cl2(g) ⇌ PCl5(g) is 49 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol

Ymorist [56]

Answer : The correct option is, (B) 0.11 M

Solution :

First we have to calculate the concentration $PCl_3$ and $Cl_2$ .

$\text{Concentration of }PCl_3=\frac{\text{Moles of }PCl_3}{\text{Volume of solution}}$

$\text{Concentration of }PCl_3=\frac{0.70moles}{1.0L}=0.70M$

$\text{Concentration of }Cl_2=\frac{\text{Moles of }Cl_2}{\text{Volume of solution}}$

$\text{Concentration of }Cl_2=\frac{0.70moles}{1.0L}=0.70M$

The given equilibrium reaction is,

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

Initially 0.70 0.70 0

At equilibrium (0.70-x) (0.70-x) x

The expression of $K_c$ will be,

$K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}$

$K_c=\frac{(x)}{(0.70-x)\times (0.70-x)}$

Now put all the given values in the above expression, we get:

$49=\frac{(x)}{(0.70-x)\times (0.70-x)}$

By solving the term x, we get

$x=0.59\text{ and }0.83$

From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.

Thus, the concentration of $PCl_3$ at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of $Cl_2$ at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of $PCl_5$ at equilibrium = x = 0.59 M

Therefore, the concentration of $PCl_3$ at equilibrium is 0.11 M

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4 years ago

Which is the net result of the proton-proton chain? 6 protons = 2 heliums + 3 positrons + 3 neutrinos + gamma rays 4 protons = 1

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Answer: 5.125 neutrinos

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3 years ago