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Andrew [12]
3 years ago
9

A roller coaster weighing 2000 kg is lifted to a height of 28 m within 30 seconds with a kind of elevator.Calculate how many kil

owatts of power the elevator has to deliver.
Physics
2 answers:
Vladimir [108]3 years ago
7 0

Answer:

Explanation:

The equation for Power is

P = Work/time to do work and the equation for work is

Work = FΔx

We first need to find the amount of work done, then we can find the power it took to do that work.

W = 2000(9.8)(28) so

W = 550,000 N*m

Now we fill that into the power equation:

P=\frac{550000}{30} gives us

P = 18000 Watts. But we need kW, so we divide by 1000 to get

P = 18 kW of power.

nexus9112 [7]3 years ago
3 0

Answer:

18.293 kilowatts

Explanation:

Given that, mass (m) = 2000 kg

Height (h) = 28m

Time(t) = 30 seconds

To find: power required in kilowatts

Now required work done will be m*g*h

= 2000*9.8*28=548800 newton

Now power required is given by (P) = work done /(time taken)

= 548800/30 = 18293.333 watts

= (18293.333 / 1000) kilowatts

= 18.293 kilowatts.

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C. It is radiation leftover from the Big Bang

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Synchronous communications satellites are placed in a circular orbit that is 3.59 107 m above the surface of the earth. What is
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Answer: 0.223 m/s^{2}

Explanation:

We can solve this with the Law of Universal Gravitation and knowing the acceleration due gravity g of an object above the surface of the planet decreases with the distance (height) of this object from the center of the planet.

Well, according to the law of universal gravitation:

F=G\frac{m_{E}m}{r^2}  (1)

Where:

F is the module of the force exerted between both bodies

G=6.67(10)^{-11}\frac{m^{3}}{kgs^{2}} is the gravitational constant

m_{E}=5.98(10)^{24} kg is the mass of the Earth

m are the mass of each communications satellite

r=R_{E}+h is the distance between the center of the Earth and the satellite

R_{E}=6.38(10)^{6} m is the radius of the Earth

h=3.59(10)^{7} m is the height of the satellite, measured from the Earth's surface

On the other hand, we know according to <u>Newton's 2nd law of motion:</u>

F=mg  (2)

Combining (1) and (2):

G\frac{m_{E}m}{r^2}=mg  (3)

Isolating g:

g=\frac{G M_{E}}{r^2}  (4)

Remembering r=R_{E}+h:

g=\frac{G M_{E}}{(R_{E}+h)^2}  (5)

g=\frac{(6.67(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24} kg)}{(6.38(10)^{6} m+3.59(10)^{7} m)^2}  

Finally:

g=0.223 m/s^{2}  

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Impulse = force * time

Substituting into the formula, we have;

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Impulse = 1000 Ns

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