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Andrew [12]
3 years ago
9

A roller coaster weighing 2000 kg is lifted to a height of 28 m within 30 seconds with a kind of elevator.Calculate how many kil

owatts of power the elevator has to deliver.
Physics
2 answers:
Vladimir [108]3 years ago
7 0

Answer:

Explanation:

The equation for Power is

P = Work/time to do work and the equation for work is

Work = FΔx

We first need to find the amount of work done, then we can find the power it took to do that work.

W = 2000(9.8)(28) so

W = 550,000 N*m

Now we fill that into the power equation:

P=\frac{550000}{30} gives us

P = 18000 Watts. But we need kW, so we divide by 1000 to get

P = 18 kW of power.

nexus9112 [7]3 years ago
3 0

Answer:

18.293 kilowatts

Explanation:

Given that, mass (m) = 2000 kg

Height (h) = 28m

Time(t) = 30 seconds

To find: power required in kilowatts

Now required work done will be m*g*h

= 2000*9.8*28=548800 newton

Now power required is given by (P) = work done /(time taken)

= 548800/30 = 18293.333 watts

= (18293.333 / 1000) kilowatts

= 18.293 kilowatts.

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A cart is pulled horizontally with a 156.6 N force to the right at a 67 degree angle with respect to the ground. The cart is mov
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Answer:

b) Vertical= 144.15N [up]

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c)  -61.19N [Left]

D) 9.8m - 144.15 = Fn

Explanation:

a) to draw the free body diagram, you would draw a square to represent the object, being the cart. The forces acting on it are Force of gravity (Fg going down), Normal force (Fn going up), Force applied (Fa going up right), and Force of friction  (Ff,going to the left, opposite of Fa).

b) So the applied force is 156.6N, and has an angle of 67. the 156.6N is the hypotenuse, so you would need to find the opposite side (vertical component), and adjacent side (horizontal component):

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sinθ = opp / hyp

sin67 = opp / 156.6

opp = 144.15N [up]

horizontal:

cosθ = adj / hyp

cos67 = adj / 156.6

adj = 61.19N [right]

c)Since the cart has constant velocity, the acceleration is 0, meaning no net force (fnet = ma, a = 0, fnet = 0), so the horizontal component of the applied force is equal to the frictional force. Heres why mathematically. (X DIRECTION ) :

Fnet = Fa + Ff

0 = Fa + Ff

-Ff = Fa.

So the force of friction has the same magnitude, but opposite direction. So since the horizontal component of applied force was 61.19 N, the frictional force will be -61.19N

d) So now we are looking at the Fnet in the y direction, which is also 0 because the car is remaining on the ground, its not going up nor down:

Fnety = 0

Fnet is composed of Fg, Fn and Fay (force applied  in y direction);

fnet = Fn + Fay + Fg.      Fn and Fay are both up, and Fg is down, so u need to subtract Fg:

fnet = Fn + Fay - Fg.

0 = Fn + 144.15 - mg

mg - 144.15  = Fn

9.8m - 144.15 = Fn

Since it didnt give you a mass thats how much you could simplify it down to, in order to get the Fn

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A spring with spring constant 31 N/m is attached to the ceiling, and a 4.5-cm-diameter, 1.5 kg metal cylinder is attached to its
aalyn [17]

Answer:

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Explanation:

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Here the forces are conserved

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