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Andrew [12]
2 years ago
9

A roller coaster weighing 2000 kg is lifted to a height of 28 m within 30 seconds with a kind of elevator.Calculate how many kil

owatts of power the elevator has to deliver.
Physics
2 answers:
Vladimir [108]2 years ago
7 0

Answer:

Explanation:

The equation for Power is

P = Work/time to do work and the equation for work is

Work = FΔx

We first need to find the amount of work done, then we can find the power it took to do that work.

W = 2000(9.8)(28) so

W = 550,000 N*m

Now we fill that into the power equation:

P=\frac{550000}{30} gives us

P = 18000 Watts. But we need kW, so we divide by 1000 to get

P = 18 kW of power.

nexus9112 [7]2 years ago
3 0

Answer:

18.293 kilowatts

Explanation:

Given that, mass (m) = 2000 kg

Height (h) = 28m

Time(t) = 30 seconds

To find: power required in kilowatts

Now required work done will be m*g*h

= 2000*9.8*28=548800 newton

Now power required is given by (P) = work done /(time taken)

= 548800/30 = 18293.333 watts

= (18293.333 / 1000) kilowatts

= 18.293 kilowatts.

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Because there is no horizontal force on the object, and we all know what happens to velocity in a direction where there is no force.
5 0
3 years ago
3000 N is exerted for 4.0 seconds on a 9500 kg object.<br><br> What is the change in momentum?
WARRIOR [948]
Force is the change in momentum over a specific time. The change of momentum is therefore the force multiplied by the time that the force acts, so 3000x4.0=12000 N s=12000 kg m/s
8 0
2 years ago
What is the international standard for measurement it is a modified version of the metric system
maxonik [38]

Answer:

SI system i think it is right

6 0
2 years ago
Two blocks of masses 3.0 kg and 5.0 kg are connected by a spring and rest on a frictionless surface. They are given velocities t
miskamm [114]

Answer:

-0.7 m/sec

Explanation:

Mass of first block = m1 =3.0 kg

Mass of second block = m2= 5.0 kg

Velocity of first block = V1= 1.2 m/s

Velocity of second block = V2 = ?

Momentum of Center of mass MVcom  is sum of both blocks momentum and is given by

MVcom= m1v1+m2v2

Where

M= mass of center of mass

Vcom= Velocity of center of mass=0 m/s (because center of mass is at rest , so Vcom = 0 m.sec)

Putting values, we get;

0= 3×1.2+5v2

==> v2=  3.6/5= - 0.7 m/s

-ve sign indicates that block 2 is moving in opposite direction of block 1

3 0
3 years ago
How much heat is needed to change 1.25 kg of steak at 100°C to water at 100°C?
cricket20 [7]

The heat required to change 1.25 kg of steak is 2825 kJ /kg.

<u>Explanation</u>:

Given, mass m = 1.25 kg,     Temperature t = 100 degree celsius

To calculate the heat required,

                                 Q = m \times L

where m represents the mass in kg,

          L represents the heat of vaporization.

When a material in the liquid state is given energy, it changes its phase from liquid to vapor and the energy absorbed in this process is called heat of the vaporization. The heat of vaporization of the water is about 2260 kJ/kg.

                                  Q = 1.25 \times 2260

                                  Q = 2825 kJ /kg.

7 0
3 years ago
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