2. Draw a ray diagram that shows the image

What sauce goes best with chicky nuggies

Sever21 [200]

Answer:

honey mustard or chick fil a sauce their special sauce

Explanation:

6 0

3 years ago

A loop of radius r = 3 cm is placed parallel to the xy-plane in a uniform magnetic field = (0.75 T) . The resistance of the loop

matrenka [14]

Answer:

i = 0.00077A

Explanation:

Given:

loop radius, r = 3.0 cm = 0.03 m

Area, A = π x r² = π x 0.03² = 0.0028 m²

Magnetic Field, B = 0.75 T

Loop resistance, R = 18 Ω

time, t = 0.15 seconds

Now,

the induced emf is given as:

EMF = - BA/t .......1

Likewise,

EMF = iR.......2

Equate 1 and 2

iR = - BA/t

i = - BA/tR

i = 0.75×0.0028/0.15×18

i = 0.0021/2.7

i = 0.00077A

8 0

3 years ago

Acceleration is defined as the change in velocity divided by

denpristay [2]

Answer:

Time elapsed

Explanation:

Acceleration is a vector quantity. It is defined as:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time elapsed

Acceleration is measured in meters per second squared (m/s^2). It must be noticed that acceleration is a vector, so it also has a direction. In particular:

- when acceleration is negative, it means that the object is slowing down, so acceleration is in opposite direction to the velocity

- when acceleration is positive, it means that the object is speeding up, so acceleration is in the same direction as the velocity

3 0

3 years ago

Savvas realize hot on the inside

Liula [17]

Answer:

Thats sounds like a club

Explanation:

8 0

3 years ago

Read 2 more answers

Water is flowing into a factory in a horizontal pipe with a radius of 0.0183 m at ground level. This pipe is then connected to a

timama [110]

Answer:

$0.0168 m^3/s$

Explanation:

We are given that

$r_1=0.0183 m$

$h_1=0$

$r_2=0.0420 m$

$h_2=12.6 m$

Let $P_1=P_2=P$

By using Bernoulli theorem

$P+\frac{1}{2}\rho v^2_1+\rho gh_1=P+\frac{1}{2}\rho v^2_2+\rho gh_2$

$\frac{1}{2}\rho v^2_1+\rho gh_1=\frac{1}{2}\rho v^2_2+\rho gh_2$

$v^2_1+2gh_1=v^2_2+2gh_2$

$A_1v_1=A_2v_2$

$v_1=\frac{A_2v_2}{A_1}$

$(\frac{A_2}{A_1})^2v^2_2+2g\times 0=v^2_2+2\times 9.8\times 12.6$

$(\frac{\pi r^2_2}{\pi r^2_1})^2v^2_2-v^2_2=246.96$

$v^2_2((\frac{r^2_2}{r^2_1})^2-1)=246.96$

$v^2_2=246.96\frac{r^4_1}{r^2_4-r^4_1}$

$v_2=\sqrt{246.96\frac{r^4_1}{r^4_2-r^4_1}}$

$v_2=\sqrt{246.96\times \frac{(0.0183)^4}{(0.042)^4-(0.0183)^4}}$

$v_2=3.038 m/s$

Volume flow rate = $A_2v_2$

Volume flow rate = $\pi r^2_2v_2=\pi (0.042)^2\times 3.038=0.0168 m^3/s$

3 0

3 years ago