Answer:
pV= nRT
Explanation:
(p1 × V1)/ T1/ (p2 × V2)/ T2
Answer:
Explanation:
CH₃COOH + NaOH = CH₃COONa + H₂O .
42.5 mL of .115 M of NaOH will contain .0425 x .115 moles of NaOH
= 48.875 x 10⁻⁴ moles NaOH
It will react with same number of moles of acetic acid
So number of moles of acetic acid in 3.45 mL = 48.875 x 10⁻⁴
number of moles of acetic acid in 1000 mL = 48.875 x 10⁻⁴ x 10³ / 3.45 moles
= 1.4167 moles
= 1.4167 x 60 gram
= 85 grams .
So 85 grams of acetic acid will be contained in one litre of acetic acid.
Answer:
The final volume in mL is 7.14 mL or 7.1 mL.
Explanation:
1.Use Boyle's Law(). Re-arrange to solve for <em> for the final volume.</em>
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<em>2. Plug in values. </em>
Answer: hello some part of your question is missing below is the missing part
when H₂O and H₂O₂ is added to Mn(OH)₂(s) and put in water bath to dissolve
answer : attached below
Explanation:
When Mn²⁺ ions are separated from the mixture, attached below are the requires reaction equations that shows the process of separation.
Mn²⁺ ions are separated to the right of the reaction equations