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Korvikt [17]
3 years ago
14

*Fill in the blank about the periodic table*

Chemistry
1 answer:
Anastaziya [24]3 years ago
7 0

Atomic number equals the number of protons or electrons. Atomic mass equals the number of protons and neutrons

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One of the few xenon compounds that form is cesium xenon heptafluoride (CsXeF7). How many moles of CsXeF7 can be produced from t
Gelneren [198K]

Answer : The number of moles of CsXeF_7 produced from the reaction is, 14 moles

Explanation :

The given balanced reaction is,

CsF(s)+XeF_6(s)\rightarrow CsXeF_7(s)

By the stoichiometry, 1 mole of cesium fluoride react with the 1 mole of xenon hexafluoride to give 1 mole of cesium xenon heptafluoride.

That means the mole ratio of CsF:XeF_6:CsXeF_7=1:1:1

As 14 moles of cesium fluoride react with the 14 moles of xenon hexafluoride to give 14 moles of cesium xenon heptafluoride.

Hence, the number of moles of CsXeF_7 produced from the reaction is, 14 moles

8 0
3 years ago
What is the volume of 5.00 mole of an unknown gas at STP
ivann1987 [24]

Answer:

What is the volume of gas at 2.00 atm and 200.0 K if its original volume was. 200.0 L at STP  How many moles of nitrogen gas will occupy a volume of 150 L at STP? n=pr 11.00atm) What is the mass of 5.00 L of NO2 gas at STP? PV = nRT.

Explanation:

5 0
3 years ago
A geologist working in a national park finds a mineral. He is carrying a kit that contains a penny, a hand lens, a piece of tile
Verizon [17]
A penny for the scratch test (low hardness)a hand lens for inspection a peice of tile for a streak test a geologic hammer to test for cleavage of fracture and the pocket knife for the scratch test (high hardness)
6 0
3 years ago
Given the following: I) N20(g) 1/2 02(g) 2 NO(g) II) N2(g) 02(g) 2 NO(g) Ke= 4.1 x 10-31 Ke= 1.7 x 10-13 Find the value of the e
tresset_1 [31]

Answer:

Answer B) 4.2x10^17

Explanation:

To produce the reaction 3 using reaction 1 and 2 we need to invert the order of the first reaction the second in the same order, as it's shown:

2NO-------->N_2O+1/2O_2 : (reaction 1' :K'_1 =1/K_1=2.4x10^ 3^0)

N_2+O_2-------->2NO: (reaction 2 :K_2 =1.7x10^-^1^3)

____________________________

N_2+1/2O_2-------->N_2O: (reaction 3)

Due to the inversion of the first equation, the equilibrium constant of the new reaction is K1'=1/K1.=2.4x10^30

Finally, the new equilibrium constant K3 is the product of the previous constants:  

K3=K1'*K2=4.2x10^17

6 0
3 years ago
18. Which one of the following is generally NOT true about elements in the
Dennis_Churaev [7]

Answer:

Statement B "Elements at the right side of the period are smaller in size" is not true.

Explanation:

Going through the rows of the elements in the period the size of the elements get continuously bigger.

7 0
3 years ago
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