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2 years ago

13

Plzz help pythagorean theorem

2 answers:

VLD [36.1K]2 years ago

8 0

Answer:

very easy 65inches

Step-by-step explanation:

follow me

puteri [66]2 years ago

4 0

144 inches

Explanation:

a^2+b^2=c^2

63^2+16^2=c^2

256+3969= 4225

Then you find the square root of 4225 which is 65

So you do 16+63+65

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2 years ago

- 3/4 × 2/5 = <br>thats what I asked for<br>

Neporo4naja [7]

Answer:

-0.3

Step-by-step explanation:

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2 years ago

What is wrong with the following equation: 4 + (10 / 5) = 6 - 2

ra1l [238]

This equation says that 6 = 4, which is incorrect. However, if there was no - 2 on the right side of the equation the answer would be correct as 6 = 6

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3 years ago

Two cars leave an intersection, one traveling west and the other south. After some time, the slower car is 7 mi nearer to the

VLD [36.1K]

Answer:

Step-by-step explanation:

let x and y be the distances of each car from the intersection after sometime.

let x<y

then y-x=7

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6 0

2 years ago

Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1

kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

4 0

2 years ago