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3 years ago

Si la fuerza de repulsión entre dos cargas es 18 × 1013

Physics

1 answer:

sattari [20]3 years ago

5 0

Answer:

Explanation:

F = kQq/r²

r = √(kQq/F)

a) r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m

r = 40 mm

b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m

r = 42 mm

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