Which of the following is a major difference between elliptical galaxies and spiral galaxies?

jeka94

The largest risks while designing a model to withstand a village include that the model does not mitigate the effects of the tsunami or only mitigates the effects partially, which would cause damages to the homes.

Designing a model to withstand the effect of any natural phenomenon such as an earthquake, fire or tsunami is not an easy task and will require the following cycle:

Designing the model.
Testing the model.
Making changes or designing a new model.

In the case of a model for tsunamis, it is likely the following problems occur:

The model does not protect the houses from tsunamis.
The model does not protect the houses completely.

This would lead to negative effects such as:

Damages in the houses.
Dead or injured people.
Destruction of infrastrcture.

Note: This question is incomplete because the context is missing; here is the missing part.

Protecting Your Model Village from Tsunamis this task, you will design a model village to withstand the effects of a tsunami.

Learn more about tsunami in: brainly.com/question/1126317

6 0

3 years ago

What is the value of the van't Hoff factor for KCl if a 1.00m aqueous solution shows a vapor pressure depression of 0.734 mmHg a

yaroslaw [1]

Answer: The Van't Hoff factor for KCl is 1.74

Explanation:

We are given:

Molality of solution = 1 m

This means that 1 mole of a solute is present in 1 kg of solvent (water) or 1000 grams of water

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of water = 1000 g

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

$\text{Moles of water}=\frac{1000g}{18g/mol}=55.56mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

Moles of solute = 1 moles

Total moles = [1 + 55.56] = 56.56 moles

Putting values in above equation, we get:

$\chi_{(solute)}=\frac{1}{56.56}=0.0177$

The equation used to calculate relative lowering of vapor pressure follows:

$\frac{p^o-p_s}{p^o}=i\times \chi_{solute}$

where,

$\frac{p^o-p_s}{p^o}$ = relative lowering in vapor pressure = 0.734 mmHg

i = Van't Hoff factor = ?

$\chi_{solute}$ = mole fraction of solute = 0.0177

$p^o$ = vapor pressure of pure water = 23.76 torr

Putting values in above equation, we get:

$\frac{0.734}{23.76}=i\times 0.0177\\\\i=1.74$

Hence, the Van't Hoff factor for KCl is 1.74

7 0

3 years ago

how many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (ch3oh)?2ch3oh 3o2 2co2 4h2o

dlinn [17]

2 CH3OH + 3 O2 = 2 CO2 + 4 H2O

2 moles CH3OH ---------------- 3 moles O2
1.33 moles CH3OH ----------- ( moles O2)

moles O2 = 1.33 x 3 / 2

moles O2 = 3.99 / 2

= 1.995 moles of O2

3 0

3 years ago

Read 2 more answers

What ions are associated with acids

kondor19780726 [428]

Blank de clan be hope she's helps youuuuuu

4 0

3 years ago

Read 2 more answers

What does ClF3 stand for

Nostrana [21]

Answer: