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Brilliant_brown [7]
3 years ago
9

Which of the following is a major difference between elliptical galaxies and spiral galaxies?

Chemistry
1 answer:
SashulF [63]3 years ago
5 0

Its A because I did it on connexus

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The mass and volume of each box is given in the chart below. Calculate the density of each box. Density = Mass/ volume which box
stira [4]

Box C will have the greatest density.

All boxes have the same volume.

Explanation:

We calculate the density using the following formula:

density = mass / volume

density of Box A = 10 g / 20 cm³ = 0.5 g/cm³

density of Box B = 30 g / 20 cm³ = 1.5 g/cm³

density of Box C = 170 g / 20 cm³ = 8.5 g/cm³

Box C will have the greatest density.

All boxes have the same volume.

Learn more about:

density

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3 years ago
Why is the piece of coal layered?
marysya [2.9K]

Answer:

Coal is layered because it is a type of sedimentary rock

Explanation:

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Wind is which type of energy? A. thermal B. mechanical C. rotational D. potential i well give you 99 pts
anzhelika [568]
I pick B. Mechanical.
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What is the chemical name for Al2(SO3)3
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Its chemical name is Aluminium Sulfite.
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3 years ago
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A rigid vessel contains 3.98 kg of refrigerant-134a at 700 kPa and 60°C. Determine the volume of the vessel and the total intern
Arada [10]

<u>Answer:</u> The volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

<u>Explanation:</u>

  • To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g    (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of container = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

700kPa\times V=\frac{3980g}{102.03g/mol}\times 8.31\text{L kPa }\times 333K\\\\V=154.21L

Converting this value into m^3, we use the conversion factor:

1m^3=1000L

So, \Rightarrow (\frac{1m^3}{1000L})\times 154.21L

\Rightarrow 0.1542m^3

  • To calculate the internal energy, we use the equation:

U=\frac{3}{2}nRT

or,

U=\frac{3}{2}\frac{m}{M}RT

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g  (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.314J/K.mol

T = temperature = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

U=\frac{3}{2}\times \frac{3980g}{102.03g/mol}\times 8.314J/K.mol\times 333K\\\\U=161994.6J

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

6 0
3 years ago
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