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Tom [10]
3 years ago
8

To assess the learning outcomes of a Statistic course, 5 students are chosen at random from each of the 30 Statistics classes an

d asked to take an assessment test. What is the sampling method used here
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer: simple random sampling

Step-by-step explanation:

In statistics, when a subset of individuals known as sample chosen from a population by a random selection of individuals such that the chances of selecting each individual is same, then the sampling method is called simple random sampling method.

Given: To assess the learning outcomes of a Statistic course, 5 students are chosen at random from each of the 30 Statistics classes.

here chances for selectin students is same.

The sampling method used here : " simple random sampling "

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Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question.
SpyIntel [72]

Let

x------> the number of multiple choice question

y------> the number of free response question

we know that

3x+8y=55 -----> equation A

x+y=15

x=15-y -----> equation B

Substitute equation B in equation A

3[15-y]+8y=55

45-3y+8y=55

5y=55-45

5y=10

y=2

Find the value of x

x=15-y

x=15-2=13

therefore

<u>the answer is</u>

the number of multiple choice question are 13

the number of free response question are 2

5 0
3 years ago
Read 2 more answers
√50 inrrational or rational
goldfiish [28.3K]

Answer:

it is irrational

Step-by-step explanation:

hav a nice dAY

7 0
3 years ago
What does<br> -$20 -$15 +$30 $2<br> Equal
ad-work [718]

Answer:

-3

Step-by-step explanation:

-20-15+30+2

-35+32

-3

4 0
3 years ago
Please help! <br> Simplify. Your answer should contain only positive exponents.
maxonik [38]

Answer:

\frac{1}{4k^3}

Step-by-step explanation:

It's already in a form that only ha positive exponents.  Just to state it though you could rewrite it as k*(4k^{4})^{-1} or k*4^{-1}*k^{-4}  The question asks for positive exponents though so yu don't need to do that.

You also need to know \frac{x^a}{x^b}=x^{a-b} so in this case \frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}

so \frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}

3 0
3 years ago
What is the standard form of the equation y=-5/2x-3 ?
butalik [34]

The standard form of an equation is the form where that equation has no fractions and is written in the form ax + by = c.


To get rid of the fractions in y = -5/2 x - 3, we need to multiply both sides by 2. That makes the equation become:


2y = -5x - 6


Now we need to get it into the form ax + by = c. We can do this by adding 5x to each side.


5x + 2y = -6 is our answer

6 0
3 years ago
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