Answer:
The most reasonable estimate for the O–S–O bond angle in hyposulfite = 106°
Explanation:
Hyposulphite (so₂²⁻) is polyatomic ion .
According to VSEPR model
Total elrctron pairs ![=\frac{1}{2} [V+X -C+A]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%20%5BV%2BX%20-C%2BA%5D)
V = Valence shell electrons of central element
X = No. of monovalent surrounding atoms
C = Cationic charge
A = Anionic charge
Total electron pairs
That is two bond pairs and two lone pairs
Answer:
Explanation:
Total mole of gases = 7.8 + 2.1 + .09 + .01 = 10
the partial pressures of the gases in a mixture
= mole fraction x Total pressure
mole fraction = mole of a gas in the mixture / total mole
partial pressure of Ng = 
= 79.014 kPa
partial pressure of O = 
= 21.273 kPa .
partial pressure of Ar = 
= .9117 kPa .
partial pressure of Co = 
= .1013 k Pa .
Answer:
3.01×10²⁴ atoms
Explanation:
Our compound is the Na₃PO₄
Sodium phosphate.
We assume, we have 5 moles of the mentioned salt.
1 mol of anything contains 6.02×10²³ atoms.
That's the Avogadro's number. The conversion is:
5 mol . 6.02×10²³ atoms /1mol = 3.01×10²⁴ atoms
Answer:
1.) The balanced equation is 3MgO(s) + 2Fe(s) ===> Fe2O3(s) + 3Mg(s)
2.) 20g of Fe2O3 will be produced by 20 ×120/160 = 15g of MgO
Explanation:
THE CORRECT EQUATION IS: MgO(s) + ___ Fe(s) ===> Fe2O3(s) + ___ Mg(s)
The balanced equation is: 3MgO(s) + 2Fe(s) ===> Fe2O3(s) + 3Mg(s)
molar mass of 3MgO = 3(24 + 16) = 120
Molar mass of Fe2O3 = 2 X 56 + 3 X 16
=112 +48 =160
From the equation, 120g of MgO Produced 160g of Fe2O3
Therefore 20g of Fe2O3 will be produced by 20 ×120/160 = 15g of MgO.
In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
Learn more: brainly.com/question/10079361