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Thepotemich [5.8K]
3 years ago
12

What are the rules for writing

Chemistry
1 answer:
Alborosie3 years ago
6 0

Answer:

When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound. ” Mono-” indicates one, “Di-” indicates two, “Tri-” is three, “Tetra-” is four, “Penta-” is five, and “Hexa-” is six, “Hepta-” is seven, “Octo-” is eight, “Nona-” is nine, and “Deca-” is ten.

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Some one help me please I'm stuck Show using two conversion factors how you would convert from 0.020 kg into mg.
julia-pushkina [17]

Answer:

=2.0x10^4mg

Explanation:

Hello there!

In this case, when performing units conversions involving two proportional factors we need to make sure we first convert to the base unit and then to the target one; thus, since 1 kg = 1000 g and 1 g = 1000 mg, we set up the following expression:

=0.020kg*\frac{1000g}{1kg} *\frac{1000mg}{1g} \\\\=2.0x10^4mg

Best regards!

4 0
3 years ago
Write structural formulas for each of the possible isomers of n-hexene that are formed by moving the position of the double bond
dem82 [27]

Answer : The structural formulas for each of the possible isomers of n-hexene are shown below.

Explanation :

Isomer : It is defined as a molecule have the same molecular formula but the different chemical structure.

There are three structural isomers of n-hexene that is based on the location of the double-bonded carbon atoms with the other atoms.

In n-hexane, 'n' shows that the chain should be straight chain there is no branching.

The three structural isomers of n-hexene are:

(1) 1-hexene

(2) 2-hexene

(3) 3-hexene

Thus, the structural formulas for each of the possible isomers of n-hexene are shown below.

5 0
3 years ago
Which of the following reactions will have the largest equilibrium constant (K) at 298 K? Which of the following reactions will
hram777 [196]

Answer:

<em>2 Hg(g) + O₂(g) → 2 HgO(s) ΔG° = -180.8 kJ </em>

Explanation:

If we know the ΔG° of a chemical reaction it is possible to calculate the equilibrium constant (k) of this procedure with the next equation:

ln Keq = -ΔG° / RT (1)

Where: Keq is equilibrium contant, ΔG° is standard state free energy change, R is gas constant and T is temperature.

Watching (1), it is possible to know that the large negative ΔG° the largest equilibrium constant. That is because R and T are always positive and to cancel the negative of equation it is necessary that ΔG° be negative.

Knowing this, is the oxidation of Hg the reaction that has the largely negative ΔG°. So, this reaction will have the largest equilibrium constant.

<em>2 Hg(g) + O₂(g) → 2 HgO(s) ΔG° = -180.8 kJ </em>

CaCO₃(s) → CaO(s) + CO₂(g) ΔG° =+131.1 kJ

3 O₂(g) → 2 O₃(g) ΔG° = +326 kJ

Fe₂O₃(s) + 3 CO(g) → 2 Fe(s) + 3 CO₂(g) ΔG° = -28.0 kJ

I hope it helps!

8 0
3 years ago
Arrange follwoing substances from lowest to highest lattice energy" MgS, KI, GAN, LiBr
sleet_krkn [62]

Answer: KI, LiBr, MgS,GaN

Explanation:

Ionic sizes are the deciding factor in lattice energy. The smaller the ion, the higher the lattice energy. Since K+> Li+ and I- is larger than Br-, LiBr will have a higher lattice energy. The size of the sulphide ion is much smaller than the nitride ion but the Gallium is much smaller due to lanthanide contraction hence the answer.

7 0
3 years ago
Please help as soon as possible!
Keith_Richards [23]

Answer:

4 because CoCO2 is in a degree And it’s all four different elements

7 0
3 years ago
Read 2 more answers
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