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Which explanation of the solar system best fits the observations of the planets and how they orbit the sun?

NeTakaya

You're right, Answer C

The dust and gas accumulate to form a solar nebula, which later on creates the star and the planets.

4 0

3 years ago

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What is the identify atom shown

Alexus [3.1K]

There is no atom shown..

7 0

3 years ago

A tin atom has 50 electrons. Electrons in the ________ subshell experience the lowest effective nuclear charge.

Alexus [3.1K]

Answer:

5p

Explanation:

We are given that a tin has 50 electrons.

We have to find in which subshell electrons experience the lowest effective nuclear charge.

We know that the electron in outermost shell experience the lowest effective nuclear charge.

Electronic configuration is given by

$50=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^2$

Outer most sub-shell is 5p. Therefore, 5p subshell experience the lowest effective nuclear charge because the distance of 5p sub-shell is large from nucleus.

Answer: 5p

5 0

3 years ago

Name the apparatus used to measure friction force? PLEASE HELP AS SOON AS POSSIBLE

melisa1 [442]

There is no apparatus for it. It is either use something like ruler and table and rub together or rub our hands, and friction force will be showed.

8 0

3 years ago

in a certain pinhole camera, the screen is 10 cm from the pinhole. When the pinhole is placed 6 cm away from a tree ,a sharp ima

vagabundo [1.1K]

Answer:

Height of the tree is <u>9.6 cm</u>

Explanation:

We know that, Magnification of an image is written as follows.

$\left(\frac{H_{i}}{H_{o}}\right)=\left(\frac{D_{i}}{D_{o}}\right)$

Where,

$\begin{array}{l}{\mathrm{H}_{0}=\text { height of the object }} \\ {\mathrm{H}_{\mathrm{i}}=\text { height of the image }} \\ {\mathrm{D}_{0}=\text { distance of the object }} \\ {\mathrm{D}_{\mathrm{i}}=\text { distance of the image }}\end{array}$

As per given question,

$\begin{array}{l}{\mathrm{H}_{1}=\text { height of the image }=\text { height of the image of the tree on screen }=16 \mathrm{cm}} \\ {\mathrm{D}_{0}=\text { distance of the object }=\text { distance of the tree from the pinhole }=6 \mathrm{cm}} \\ {D_{1}=\text { distance of the image }=\text { distance of the image from the pinhole }=10 \mathrm{cm}} \\ {\mathrm{H}_{0}=\text { height of the object }=\text { height of the tree }}\end{array}$

Substitute the values in the above formula,

$\begin{array}{l}{\left(\frac{H_{i}}{H_{o}}\right)=\left(\frac{D_{i}}{D_{o}}\right)} \\ {\left(\frac{16}{H_{o}}\right)=\left(\frac{10}{6}\right)} \\ {\mathrm{H}_{\mathrm{o}}=\left(\frac{16 \times 6}{10}\right)} \\ {\mathrm{H}_{\mathrm{o}}=9.6 \mathrm{cm}}\end{array}$

Height of the tree is 9.6 cm.

8 0

3 years ago