The answer should be C. Encourage his daughter to make friends with the new boy.
Hope this helps and have a happy new year
Answer:
The maximum wavelength is 492 nm.
Explanation:
Given that,
Angular separation 
Suppose a telescope with a small circular aperture of diameter 2.0 cm.
We need to calculate the maximum wavelength
Using formula of angular separation
Put the value into the formula
For small angle 
Hence, The maximum wavelength is 492 nm.
Boyle's law is modeled by the equation p1v1=p2v2.
Answer:
9) This is a case of deceleration
10)-0.8 ms-2
b) acceleration is the change in velocity with time
11)
a) 100 ms-1
b) 100 seconds
12) 10ms-1
13) more information is needed to answer the question
14) - 0.4 ms^-2
15) 0.8 ms^-2
Explanation:
The deceleration is;
v-u/t
v= final velocity
u= initial velocity
t= time taken
20-60/50 =- 40/50= -0.8 ms-2
11)
Since it starts from rest, u=0 hence
v= u + at
v= 10 ×10
v= 100 ms-1
b)
v= u + at but u=0
1000 = 10 t
t= 1000/10
t= 100 seconds
12) since the sprinter must have started from rest, u= 0
v= u + at
v= 5 × 2
v= 10ms-1
14)
v- u/t
10 - 20/ 25
10/25
=- 0.4 ms^-2
15)
a=v-u/t
From rest, u=0
8 - 0/10
a= 8/10
a= 0.8 ms^-2
Path 2.
Displacement is the direction and magnitude of an object from its starting point, so path 2 is the direct route you would need to take to find direction and magnitude.
