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muminat
3 years ago
14

Ron wants to install an energy efficient and long lasting device for lighting in his new home. Which device should he use?

Engineering
1 answer:
slamgirl [31]3 years ago
8 0

Answer:

Led tube lights.

Explanation:

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Print a message telling a user to press the letterToQuit key numPresses times to quit. End with newline. Ex: If letterToQuit = '
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Vb.Net

msgbox ("Press "q" twice to quit", msgboxstyle.information)

if char.q = keypress and keypress.count = 2 then

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You need to wear respiratory PPE whenworking around materials that may contain asbestos
choli [55]

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to prevent asbestos fibers poisoning

Explanation:

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Explain the new Beryllium Standard
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True or false: The maximum tensile force a solid, cylindrical wire can withstand increases as the thickness of the wire increase
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7 0
3 years ago
Purely resistive loads of 24kW, 18kW and 12kW are connected between the neutral and the red, yellow and the blue respectively of
seraphim [82]

Answer:

The phase current in each line conductor are;

I_{R} = 100.17 < 0A

I_{Y} = 75.13< - 120A

I_{B} = 50.08

Explanation:

Given the following data;

Red phase = 24kW,

Yellow phase = 18kW

Blue phase = 12kW

Line voltage = 415V

For a star connected system, we have;

Phase voltage (V_{p} ) = \frac{Line voltage}{\sqrt{3}}

Phase voltage (V_{p} ) = \frac{415}{\sqrt{3}}

Phase voltage (V_{p} ) = 239.6V

The phase sequence for RYB is given by;

V_{R} = 239.6

Phase current (I) = \frac{Phase power}{Phase voltage}

Hence, I = \frac{P}{V}

<em>For the Red phase;</em>

I_{R} = \frac{24000}{239.6

I_{R} = 100.17 < 0A

<em>For the Yellow phase;</em>

I_{Y} = \frac{18000}{239.6

I_{Y} = 75.13< - 120A

<em>For the Blue phase;</em>

I_{B} = \frac{12000}{239.6

I_{B} = 50.08

For the line neutral;

I_{N} =\sqrt{ (I_{R}^{2} +I_{Y}^{2}+I_{B}^{2}-I_{R}I_{Y}-I_{Y}I_{B}-I_{R}I_{B}

Substituting we have, I_{N} = 43.29A

6 0
3 years ago
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