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chubhunter [2.5K]

2 years ago

8

What is the gain in gravitational potential energy of a body of weight 2000N as it rises from a height of 20m to a height of 25

m above the Earth's surface

1 answer:

monitta2 years ago

8 0

Answer:

Explanation:

GPE =weight * height

= 2000*(25-20)

= 10000 J

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According to Charles's law, for a fixed quantity of gas at constant pressure, which of the given quantities is constant? Accordi

Naddik [55]

Charles's <span>law is also known as the law of volumes explained the relation between the volume of gas and its temperature.

Charles's law states that: " At constant pressure, the volume of a certain mass of gas is directly proportional to its temperature in kelvin".
This means that:
V = T*constant
V/T = constant

Based on this, the correct choice is:
</span><span>a) V/T</span>

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Runner A takes 45 s to run 400 m. Runner B takes 48 s to run the same distance. Which runner has the greater average speed?

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Runner A because they completed it in a less amount of time

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lilavasa [31]

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An observer on Earth sees rocket 1 leave Earth and travel toward Planet X at 0.3c. The observer on Earth also sees that Planet X

Verizon [17]

Answer:

0.625 c

Explanation:

Relative speed of a body may be defined as the speed of one body with respect to some other or the speed of one body in comparison to the speed of second body.

In the context,

The relative speed of body 2 with respect to body 1 can be expressed as :

$u'=\frac{u-v}{1-\frac{uv}{c^2}}$

Speed of rocket 1 with respect to rocket 2 :

$u' = \frac{0.4 c- (-0.3 c)}{1-\frac{(0.4 c)(-0.3 c)}{c^2}}$

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3 years ago

A person is trying to lift a crate that has a mass of 30 kg. The normal force of the floor is currently supplying 150N of force.

alexdok [17]

Here when an object is placed on the level floor then in that case there are two forces on the object

1). Weight of object downwards (mg)

2). Normal force due to floor which will counterbalance the weight (N)

so when no force is applied on the box at that time normal force is counter balanced by weight.

Now here it is given that A person tried to lift the box upwards

So now there are two forces on the box

1). Applied force of person

2). Normal force due to ground

So now these two forces will counter balance the weight of the crate

So we can write an equation for force balance like

$F_g = F_n + F_a$

given that

$F_g = mg$

here

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g = acceleration due to gravity = 10 m/s^2

$F_n = 150 N$

now from above equation

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So force applied by the person must be 150 N

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3 years ago