The equation for the reaction of hydrogen and oxygen is:
Thus, the theoretical yield of water is 9 grams.
To solve this problem you would add 3/4 to 7 1/3.
3 22
4 3
9 88
12 12
97
12
8 1/12
The final answer would be 8 and 1/12
To take the percent by mass of this element, we use the
formula:
% mass = (mass of element / mass of ore) * 100%
% mass = (47.5 g / (660 kg * 1000 g / kg)) * 100*
<span>% mass = 7.20 x 10^-3 %</span>
Answer:
Na⁺ and HCO⁻₃
Explanation:
When baking soda is dissolve in water it fully ionized into positive and negative ions.
NaHCO₃ + H₂O → Na⁺ + HCO⁻₃
The Na⁺ than react with OH⁻ of water and produced NaOH while HCO⁻₃ react with H⁺ and produce H₂CO₃. This carbonic acid than break to produced carbon dioxide and water.
H₂CO₃ → H₂O + CO₂
Properties of baking soda:
It is odorless compound.
It is solid at room temperature.
It is used in medicine to cure the acidity of stomach.
It is used to make baking powder.
Answer:
The ratio of HC2H3O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) to HC2H3O2(aq) in the flask after the addition of 1.0mL of NaOH(aq) is 15 : 19 .
Explanation:
HC2H3O2 is CH₃⁻ COOH, which is also known as Acetic acid.
IUPAC name of this compound is Ethanoic acid.
Acetic acid has a basicity of 1. so there is one acidic hydrogen is acetic acid.
Given that, equivalence point was reached when 20.0mL of NaOH is added.
let the normality of acetic acid is N₁ and that of NaOH is N₂.
volume of acetic acid is V₁ and that of NaOH is V₂.
Equivalence point occurs when, N₁ × V₁ = N₂ × V₂.
⇒ N₁ × V₁ = N₂ × 20.
after the addition of 5.0mL of NaOH(aq), remaining N₁ × V° = N₂ × (20 - 5).
= N₂ × 15.
after the addition of 1.0mL of NaOH(aq), remaining N₁ × Vˣ = N₂ × (20 - 1).
= N₂ × 19.
⇒ V° : Vˣ = 15 : 19 .
⇒
