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Svetradugi [14.3K]
3 years ago
10

Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict whet

her or not this reaction will be spontaneous at this temperature. 2NO(g) + O2(g) → 2NO2(g) ΔH = -114 kJ Consider the following reaction at constant . Use the information here to determine the value of at 355 . Predict whether or not this reaction will be spontaneous at this temperature. 2(g) + (g) 2(g) = -114 ΔSsurr = +114 kJ/K, reaction is spontaneous ΔSsurr = -114 kJ/K, reaction is spontaneous ΔSsurr = -321 J/K, reaction is spontaneous ΔSsurr = +321 J/K, reaction is spontaneous ΔSsurr = +114 J/K, it is not possible to predict the spontaneity of this reaction without more information.g
Chemistry
1 answer:
Sloan [31]3 years ago
8 0

The given reaction is as follows:

2NO (g) + O₂ (g) = 2NO₂ (g), ΔH = -114 kJ

It is known that dSsurr = -dHsys / T (Temp = 355 K)

So,  dSsurr = - (-114 × 1000) / 355

dSsurr = +321.12 J/K

Hence, the value of dSsurr is +321.12 J/K

For a reaction to be spontaneous, dG<0,

Also dStotal = dSsys + dSsurr > 0

It is known that dG = dHsys - TdSsys,

Now let us assume,

dG<0

Also, dStotal = dSsys + dSsurr > 0

(-114 × 1000) - (355 × dSsys) <0

355 × dSsys > -114 × 1000

dSsys > -321

dSsys >dSsurr

dSsys + dSsurr > 0

dStotal > 0

Thus, the assumption is correct, and the given reaction is spontaneous. Hence, the final answer is Ssurr = +321 J/K reaction is spontaneous.



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Now, formula used to calculate the new volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{0.60 atm \times 61 L}{183 K} = \frac{1 atm \times V_{2}}{273.15 K}\\V_{2} = 54.63 L

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What is the molarity of a stock solution if 60 mL were used to make 150 mL of a .5M solution
kirza4 [7]

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The answer to your question is 1.25 M

Explanation:

Data

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Process

1.- Write the dilution formula

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-Solve for Molarity 1

       Molarity 1 = Molarity 2 x Volume 2 / Volume 1

-Substitution

        Molarity 1 = (0.5)(150) / 60

-Simplification

        Molarity = 75 / 60

-Result

        Molarity = 1.25 M

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