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igor_vitrenko [27]
3 years ago
6

A solar cell, 3.0 cm square, has an output of 350 mA at 0.80 V when exposed to full sunlight. A solar panel that delivers close

to 1.0 A of current at an emf of 120 V to an external load is needed. How many cells will you need to create the panel? How big a panel will you need, and how should you connect the cells to one another? How can you optimize the output of your solar panel?

Physics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

You will need 450 cells (3 cm each) to meet the voltage/current requirement.

The panel must be 3 cells in one side, by 150 cell in another side. 1350 cm^2 or 0.135 m^2. They must be connected 3 in row in parallel (to add current), then each of the former group must be connected in series to meet the voltage, so it would be 150 rows of connected in series.

The panel can be optimized using a voltage inverter, to convert current to voltage. In this way, less cells can be used achieving the same output specs.

Explanation:

To meet the voltage:

120 [v] required voltage

0.8 [v] voltage of each cell

\frac{120}{0.8} =150[v]\\

So we need 150 cells in series for the voltage.

To meet the current

1.0 [A]      Required current

350[mA]=0.35[A] cell current

1/0.35=3 cell So we need 3 cells in parallel to add the currents and meet the requirement.

See the attached figure

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Explanation:

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3 years ago
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a student drops an object from the top of a building which is 19.6 m high. How long does it take the object to fall to the groun
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Here's a formula that's simple and useful, and if you're really in
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This one is so simple and useful that I'd suggest memorizing it,
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This formula tells how far an object travels in how much time,
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8 0
3 years ago
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a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what w
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Answer:

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We have to find the effort distance.

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Using the formula

800\times 10=200\times effort\;distance

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Effort distance=\frac{8000}{200}

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