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3 years ago

Calculate the mass of 3.5 mol C6H6

Chemistry

1 answer:

Lilit [14]3 years ago

4 0

(3.5mol)(24.106 g/1mol c6h6) =84.371 g C6H6

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When a hydrochloric acid solution is combined with a potassium hydroxide solution, an acid-base reaction occurs Write a balanced

Svetach [21]

Answer:

HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)

Explanation:

Hydrochloric acid is an acid because it releases H⁺ in an aqueous solution.

Potassium hydroxide is a base because it releases OH⁻ in an aqueous solution.

When an acid reacts with a base they form a salt and water. This is a neutralization reaction. The neutralization reaction between hydrochloric acid and potassium hydroxide is:

HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)

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3 years ago

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Stolb23 [73]

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2 years ago

What is the rate constant of a reaction if rate = 1 x 10-2 (mol/L)/s, [A] is 2 M,

boyakko [2]

The rate constant of a reaction : 8.3 x 10⁻⁴

<h3>Further explanation</h3>

Given

rate = 1 x 10⁻² (mol/L)/s, [A] is 2 M, [B] is 3 M, m = 2, and n = 1

Required

the rate constant

Solution

For aA + bB ⇒ C + D

Reaction rate can be formulated:

$\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}$

the rate constant : k =

$\tt k=\dfrac{rate}{[A]^m[B]^n}\\\\k=\dfrac{1.10^{-2}}{2^2\times 3^1}\\\\k=8.3\times 10^{-4}$

8 0

2 years ago

Read 2 more answers

Answer this: 15/x = 23/3<br> and this: 30/x = 90/3

prohojiy [21]

Answer:

the 1st one is impossible second is x = 1

Explanation:

7 0

2 years ago

Read 2 more answers

1. Sulfuric acid is formed when sulfur dioxide gas reacts with oxygen gas and water. Write a balanced chemical equation for the

tekilochka [14]

Answer:

1. Balanced chemical for the given chemical reaction is :

$2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow 2H_2SO_4(aq)$

number of mole of sulphuric acid produced = 12.5 mol

number of mole of oxygen required=6.25 mol

Explanation:

1. Balanced chemical for the given chemical reaction is :

$2SO_2(g) +O_2(g) +2H_2O(l) \rightarrow 2H_2SO_4(aq)$

from above balanced equation it is clearly that ,

2 mole of sulpher dioxide gives 2 mole of sulphuric acid

1 mole of sulpher dioxide gives 1 mole of sulphuric acid

therefore,

12 .5 mole of sulpher dioxide will givs 12.5 mole of sulphuric acid

number of mole of sulphuric acid produced = 12.5 mol

2 mole of sulphur dioxide needs 1 mole of oxygen gas

so,

1 mole of sulphur dioxide needs 0.5 mole of oxygen gas

therefore 12.5 of sulphur dioxide needs $12.5 \times 0.5$ mole of oxygen

number of mole of oxygen required=6.25 mol

4 0

2 years ago