Calculate the mass of 3.5 mol C6H6

Which element has the lowest ionization energy?

UNO [17]

C the answer is cesium, study's show that it has the lowest ionization out of all elements. Hope this helped!

4 0

2 years ago

Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of

Neko [114]

Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}$

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles$

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

$\eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles$

Finally, the mass of SiH₄ is:

$m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g$

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!

3 0

2 years ago

Which change in the sun’s gravity would occur if the sun’s mass were reduced by one-half?(1 point)

Kisachek [45]

Answer:

Gravity or the gravitational force is defined as the force of attraction occurring between all states of matter. The sun’s gravity, mass, and radius plays a crucial role in the properties of the Sun.

Explanation:

The gravity of an object can be determined using the formula:

$\text{g}&=\frac{\text{GM}}{\text{R}^{2} }}$

Now, according to the question, the mass of the sun is halved, which will be written as:

$\text{g}&=\frac{\text{G}\frac{\text{M}}{2}}{\text{R}^{2} }}$

Thus, according to the equation, the mass of an object is directly proportional to the gravitational field. since, the mass of the Sun is reduced to half, the gravity of the Sun will be halved.

8 0

2 years ago

Read 2 more answers

If the container is closed and the ethanol is allowed to reach equilibrium with its vapor, how many grams of liquid ethanol rema

SVETLANKA909090 [29]

Explanation:

Let us assume that the given data is as follows.

V = 3.10 L, T = $19^{o}C$ = (19 + 273)K = 292 K

P = 40 torr (1 atm = 760 torr)

So, P = $\frac{40 torr}{760 torr} \times 1 atm$

= 0.053 atm

n = ?

According to the ideal gas equation, PV = nRT.

Putting the given values into the above equation to calculate the value of n as follows.

PV = nRT

$0.053 atm \times 3.10 L = n \times 0.0821 L atm/mol K \times 292 K$

0.1643 = $n \times 23.97$

n = $6.85 \times 10^{-3}$

It is known that molar mass of ethanol is 46 g/mol. Hence, calculate its mass as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

$6.85 \times 10^{-3} = \frac{mass}{46 g/mol}$

mass = $315.1 \times 10^{-3}$ g

= 0.315 g

Thus, we can conclude that the mass of liquid ethanol is 0.315 g.

4 0

2 years ago

According to the law of conservation of mass, what is the same on both sides of a balanced chemical equation?

Firlakuza [10]

According to the law of conservation of mass, what is the same on both sides of a balanced chemical equation?

A. the volume of the substances

B. the subscripts

C. the total mass of atoms

D. the coefficients

Answer:

A balanced equation demonstrates the conservation of mass by having the same number of each type of atom on both sides of the arrow.

Explanation:

Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. ... Use coefficients of products and reactants to balance the number of atoms of an element on both sides of a chemical equation.

Consider the balanced equation for the combustion of methane.

CH

4

+

2O

2

→

CO

2

+

2H

2

O

All balanced chemical equations must have the same number of each type of atom on both sides of the arrow.

In this equation, we have 1

C

atom, 4

H

atoms, and 4

O

atoms on each side of the arrow.

The number of atoms does not change, so the total mass of all the atoms is the same before and after the reaction. Mass is conserved.

Here is a video that discusses the importance of balancing a chemical equation.

8 0

2 years ago