Question

In a large population, 71 % of the people have been vaccinated. If 4 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?

Answer 1

Answer:

The answer is "0.9929"

Step-by-step explanation:

$\text{The distribution in binomials is n = 4 and p = 0.71.}\\\\\text{Vaccinated Pr(AT LEAST ONE) = 1-pr( no people vaccinated ).}$

$= 1 - Bin (n=4, k =0, p=0.71) \\\\= 1 - C(4,0) \times 0.71^0 \times (1-0.71)^{4-0} \\\\= 1 - (1 \times 0.29^4)$

$= 1 - (1 \times 0.00707281)\\\\=0.9929$