A :-) F = mv^2 by r
Given - m = 500 kg
v = 80.0 m/s
r = 450 m
Solution -
F = mv^2 by r
F = 500 x (80)^2 by 450
F = 500 x 6400 by 450
( cut 500 and 450 because 5 x 100 = 5 , 5 x 90 = 450 and also 90 and 6400 because 90 x 70 = 6400 )
F = 100 x 70
F = 7000
.:. The centripetal force is 7000 N
The static frictional force is greater than the kinetic frictional force, so the static frictional force is greater than 1200 N.
Answer:
The magnitude of force on P is 2.75 N
The magnitude of force on Q is 7.15 N
Solution:
As per the question:
Mass of the object, M = 11.0 kg
Acceleration of the object when the forces are directed leftwards, a = 
Acceleration when the forces are in opposite direction, a' = 
Now,
The net force on the object in first case is given by:
(1)
The net force on the object in second case is given by:
(2)
Adding both eqn (1) and (2):


Putting the above value in eqn (1):


Answer:
There are so many questions which one you don't know
I'm pretty sure the energy an object acquires when exposed to a force is known was potential energy.