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2 years ago

In a lunar eclipse, does the Moon enter the shadow of Earth from the east or west side? Explain.

Physics

2 answers:

arlik [135]2 years ago

5 0

Answer:

Option-

In a lunar eclipse, the Moon enters the shadow of Earth from the west side of the orbit.

Explanation:

Lunar Eclipse:

The lunar eclipse occurs when the Earth's position inside the orbital system or pattern of the solar system. As the Moon comes behind the Earth in more simplified words, as the Moon comes from the west side of the orbit. While the shadow of the Earth falls on the Moon's body.

For example:

The lunar eclipse occurs in the US in a very specific manner as we observe the lunar eclipse starts from the west coast of the United states, as it goes all the way towards the east coast of the state or the country.

puteri [66]2 years ago

4 0

Answer:

Explained

Explanation:

In lunar eclipse, the Moon enter the shadow of Earth from the west side. This happens because that the direction of moon's orbit around the Earth. Just observe moon at a Night , note its apparent position in the night sky and one the next night note its new position, you find that moon has moved eastward. Therefore in Moon shadow the earth from west to east

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Ozone, O3 methane, CH4 oxygen gas, O2 Are classified as

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I would think compounds.

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2 years ago

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The inner planets are DIFFERENT from the outer planets mainly because they are A) colder. B) larger. C) comprised of gas. D) com

Vaselesa [24]

The inner planets are not colder or larger than the outer ones,
and they're not comprised of gas.

The inner planets are the ones that are made of rock. ( D ).

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2 years ago

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Un camion de envios se encuentra detenido en una señal de pare, permitiendo que pase una ambulancia. Inicia su recorrido y al ca

Nesterboy [21]

Answer:

$0.741\ \text{m/s}^2$

Explanation:

v = Velocidad final = $40\ \text{km/h}=\dfrac{40}{3.6}\ \text{m/s}$

u = Velocidad inicial = 0

t = Tiempo empleado = 15 s

a = Aceleración

De las ecuaciones cinemáticas tenemos

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{40}{3.6}-0}{15}\\\Rightarrow a=0.741\ \text{m/s}^2$

La aceleración del camión en el primer intervalo de tiempo es $0.741\ \text{m/s}^2$ .

4 0

2 years ago

A truck has shock absorbers with a spring constant of 24200 N/m. When it hits a bump, it oscillates at 0.429 Hz. What is the mas

siniylev [52]

Answer:

3331.5 kg

Explanation:

Given:

Spring constant of the spring (k) = 24200 N/m

Frequency of oscillation (f) = 0.429 Hz

Let the mass be 'm' kg.

Now, we know that, a spring-mass system undergoes Simple Harmonic Motion (SHM). The frequency of oscillation of SHM is given as:

$f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}$

Rewrite the above equation in terms of 'm'. This gives,

$2\pi f=\sqrt{\frac{k}{m}}\\\\Squaring\ both\ sides,\ we\ get:\\\\(2\pi f)^2=\frac{k}{m}\\\\m=\frac{k}{4\pi^2 f^2}$

Now, plug in the given values and solve for 'm'. This gives,

$m=\frac{24200\ N/m}{4\pi^2\times (0.429\ Hz)^2 }\\\\m=\frac{24200\ N/m}{4\pi^2\times 0.184\ Hz^2}\\\\m\approx3331.5\ kg$

Therefore, the mass of the truck is 3331.5 kg.

3 0

2 years ago

Sometimes a person cannot clearly see objects close up or far away. To correct this type of vision, bifocals are often used. The

Alexxx [7]

Answer:

The power of top half of the lens is 0.55 Diopters.

Explanation:

Since, the person can see an object at a distance between 34 cm and 180 cm away from his eyes. Therefore, 180 cm must be the focal length of the upper part of lens, as the top half of the lens is used to see the distant objects.

The general formula for power of a lens is:

Power = 1/Focal Length in meters

Therefore, for the top half of the lens:

Power = 1/1.8 m

Power = 0.55 Diopters

3 0

2 years ago