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3 years ago

In a lunar eclipse, does the Moon enter the shadow of Earth from the east or west side? Explain.

Physics

2 answers:

arlik [135]3 years ago

5 0

Answer:

Option-

In a lunar eclipse, the Moon enters the shadow of Earth from the west side of the orbit.

Explanation:

Lunar Eclipse:

The lunar eclipse occurs when the Earth's position inside the orbital system or pattern of the solar system. As the Moon comes behind the Earth in more simplified words, as the Moon comes from the west side of the orbit. While the shadow of the Earth falls on the Moon's body.

For example:

The lunar eclipse occurs in the US in a very specific manner as we observe the lunar eclipse starts from the west coast of the United states, as it goes all the way towards the east coast of the state or the country.

puteri [66]3 years ago

4 0

Answer:

Explained

Explanation:

In lunar eclipse, the Moon enter the shadow of Earth from the west side. This happens because that the direction of moon's orbit around the Earth. Just observe moon at a Night , note its apparent position in the night sky and one the next night note its new position, you find that moon has moved eastward. Therefore in Moon shadow the earth from west to east

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A rope.that is 1.50m long exhibits a standing wave pattern with 6 nodes if the frequency of the waves is 75.0 hz what is the vel

Sonja [21]

I think he answer is 34.32

4 0

3 years ago

What metric unit would you use to measure the weight of an elephant

Tems11 [23]

Answer:

kilograms

Explanation:

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3 years ago

A space probe is coasting through space at a steady speed of 100p feet per second. the booster rocket fires for 1/2 seconds so t

aleksandr82 [10.1K]

Answer:

Acceleration: $9800 ft/s^2$

Explanation:

The acceleration of an object is equal to the rate of change of velocity:

$a=\frac{v-u}{t}$

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

For the space probe in this problem, we have:

u = 100 ft/s (initial velocity)

v = 5000 ft/s (final velocity)

t = 0.5 s (time taken)

Therefore, the acceleration is

$a=\frac{5000-100}{0.5}=9800 ft/s^2$

6 0

3 years ago

A gas had a initial volume of 168 cm at a temperature of 255 k and a pressure of 1.6 atm the pressure of the gas decreased to 1.

Mademuasel [1]

P₁V₁ / T₁ = P₂V₂ / T₂

1.6 × 168 /255 = 1.3 × V₂ / 285

V₂ = 1.6 × 168 × 285 / (1.3 × 255)

V₂ = 231.095

The final volume = 231 cm³

7 0

3 years ago

A sling is used to give a stone an initial velocity of 20 at an angle of 30 above the horizontal. The stone travels through the

Luba_88 [7]

Answer:

Option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Explanation:

Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given as

R = (u² sin 2θ)/g

where

u = initial velocity of the projectile = 20 m/s

θ = angle above the horizontal at which the projectile was launched = 30°

g = acceleration due to gravity = 9.8 m/s²

R = (30² sin 60°) ÷ 9.8

R = 78.53 m

So, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Hope this Helps!!!

7 0

3 years ago