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2 years ago

What is affected by an airplane's speed?

2 answers:

8 0

As an aircraft increases speed (TAS) the airflow over some part of the fuselage or wings may be accelerated up to the speed of sound and a shock wave will form. These shock waves cause more drag, less lift, turbulent flow, and a reduction in effectiveness or even a reversal of control reactions.

ratelena [41]2 years ago

6 0

Airplanes produce lift from the air moving over their wings. Stall speed is a metric that refers to the minimum speed required for an airplane to produce lift. When airplanes fly slower than their respective stall speed, they won't produce lift. ... If an airplane's speed drops below its stall speed, it won't produce lift.

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Science and math people where you at

PilotLPTM [1.2K]

For the second question you’re solving for resistance. resistance= voltage/ current. 120/0.5= 240. the answer is 240 ohms
for the third question you would do 2*4 since it’s asking for voltage, the answer is 8 volts :)

8 0

3 years ago

The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. Calculate the energ

olya-2409 [2.1K]

Answer: 8400 J

Explanation:

The formula referenced in the question is:

$Q=m. c. \Delta T$

Where:

$Q$ is the thermal energy

$m=100g \frac{1 kg}{1000 g}=0.1 kg$ is the mass of the water sample

$c=4200 \frac{J}{kg\°C}$ is the specific heat capacity of water

$\Delta T=20\°C$ is the variation in temperature

Solving:

$Q=(0.1 kg)(4200 \frac{J}{kg\°C})(20\°C)$

$Q=8400 J$ This is the thermal energy released

8 0

2 years ago

A lead nucleus is spherical with a radius of about 7 ✕ 10⁻¹⁵ m. The nucleus contains 82 protons (and typically 126 neutrons). Be

Komok [63]

Answer:

∈= $3.1584x10^{26} \frac{V}{m}$

Explanation:

Using the Gauss Law to determine the electric field of the net flux at the surface of the nucleus

∈ $=\frac{P}{E_{o}}$

The P is the charge density and 'Eo' is the constant of permittivity in free space

to find P

$P=\frac{q}{V}$

$V=\frac{4}{3}*\pi*r^3$

$V=\frac{4}{3}\pi*(7x10^{-15})^3$

$V=2.932x10^{-14} m^3$

$P=\frac{82C}{2.932x10^{-14}m^3}=2.7965x10^{15} \frac{C}{m^3}$

So replacing

∈ $=\frac{2.7965x10^{15}\frac{C}{m^3}}{8.8542x10^{-12}\frac{C^2}{N*m^2}}$

∈= $3.1584x10^{26} \frac{V}{m}$

3 0

2 years ago

Why is water known as the "Universal Solvent"?

kompoz [17]

<span>Water is known as the universal solvent because it is capable of dissolving a variety of substances, more than any other liquid.

Hope this helps!</span>

4 0

3 years ago

100 kw of power is delivered to the other side of a city by a pair of power lines with the voltage difference of 13014.1 v.

FinnZ [79.3K]

A) The power delivered to the lines is
$P_{in}= 100 kW=1 \cdot 10^5 W$
And the voltage at which the lines work is
$V=13014.1 V$
Since the power delivered is the product between the voltage and the current:
$P=VI$
We can find the current flowing in the lines:
$I= \frac{P}{V}= \frac{1 \cdot 10^5 W}{13014.1 V}=7.68 A$

b) The voltage change along each line can be found by using Ohm's law:
$\Delta V = IR = (7.68 A)(10 \Omega)=76.8 V$

c) The power wasted as heat along each line is given by:
$P_d = I^2 R = (7.68 A)^2 (10 \Omega) = 590 W$
And since we have 2 lines, the total power wasted as heat in both lines is
$P_d = 2 \cdot 590 W=1180 W$

6 0

2 years ago