Answer:
B. 2.3mm
Explanation:
The correct answer for the given question is B. 2.3mm. Some aircraft are made are fabricated from aluminium which has plane stain fracture toughness. In the given scenario the plane stain toughness is
Ktc = 40 [ MPa 
]
When the Ktc increases the fracture will appear on the aircraft. In this case the maximum crack until the fracture failure is 2.5mm.
Answer:
During film condensation on a vertical plate, heat flux at the top will be higher since the thickness of the film at the top, and thus its thermal resistance, is lower.
Explanation:
https://www.docsity.com/pt/cengel-solution-heat-and-mass-transfer-2th-ed-heat-chap10-034/4868218/
https://arc.aiaa.org/doi/pdf/10.2514/1.43136
https://arxiv.org/ftp/arxiv/papers/1402/1402.5018.pdf
There are NO “lead weights inside tires”!
Balancing of the entire wheel (rim plus tire ) is done by correctly fitting the tire to the rim to begin with (new tires have printed coloured marks identifying the heavy and light bits), and then by adding balancing weights to the metal rim, usually made of lead but not always.
If you’re recycling rims then yes, remove the weights and recycle those separately.
Answer:
h1 = 290.16kj/kg
P = 1.2311
Prandil expression at 8
P=p1/p7×pr
=8(1.2311)
=9.85
Enthalpy state at 8 corresponding to 9.85
h1 = 526.13kj/kg
Now prandtl state at 9 that correspond to 1400k.
h9 = 1515.42kj/kg
Pr = 450.5
Prandtl expression at state 10
P= p10/p9×pr
=1/8(450.5)
=56.31
Enthalpy at state 10 corresponding to prandtl 56.31
h10 = 860.39kj/kg
At 520k
h11 = 523.63kj/kg
Answer:
aluminum bar carrying a higher load than steel bar
Explanation:
Given data;
steel abr
diameter = 5 mm
stress = 500 MPa
aluminium bar
diameter = 10 mm
stress = 150 MPa
we know
stress = laod/area
for steel bar
solving for P
P = 9817.47 N
for Aluminium bar
solving for P
P = 11790 N
aluminum bar carrying a higher load than steel bar
