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Varvara68 [4.7K]
3 years ago
5

A baseball pitcher throws a ball horizontally at a speed of 34.0 m/s. A catcher is 18.6 m away from the pitcher. Find the magnit

ude, in meters, of the vertical distance that the ball drops as it moves from the pitcher to the catcher. Ignore air resistance.
Physics
1 answer:
Sidana [21]3 years ago
6 0

To develop this problem, it is necessary to apply the concepts related to the description of the movement through the kinematic trajectory equations, which include displacement, velocity and acceleration.

The trajectory equation from the motion kinematic equations is given by

y = \frac{1}{2} at^2+v_0t+y_0

Where,

a = acceleration

t = time

v_0 = Initial velocity

y_0 = initial position

In addition to this we know that speed, speed is the change of position in relation to time. So

v = \frac{x}{t}

x = Displacement

t = time

With the data we have we can find the time as well

v = \frac{x}{t}

t = \frac{x}{v}

t = \frac{18.6}{34}

t = 0.547s

With the equation of motion and considering that we have no initial position, that the initial velocity is also zero then and that the acceleration is gravity,

y = \frac{1}{2} at^2+v_0t+y_0

y = \frac{1}{2} gt^2+0+0

y = \frac{1}{2} gt^2

y = \frac{1}{2} 9.8*0.547^2

y = 1.46m

Therefore the vertical distance that the ball drops as it moves from the pitcher to the catcher is 1.46m.

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Water, oil and silver are poured into the vessel
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The height of the oil column above the water in the vessel is determined as 2 cm.

<h3>Pressure of the vessel</h3>

The pressure of the vessel due to water, oil and silver poured into the vessel is determined from mercury column.

let level of mercury = 20 cm + 0.5 cm = 20.5 cm

20.5 cmHg = 205 mmHg

1 mmHg = 133.32 Pa

205 mmHg = 27,330.6 Pa

<h3>Height of the liquids in the vessel</h3>

P = ρgh

where;

ρ is the density of water, oil and silver respectively

ρ = 1000 kg/m³ + 881 kg/m³ + 10,800 kg/m³ = 12,681 kg/m³

h = P/(ρg)

h = (27,330.6) / (12,681 x 9.8)

h = 0.22 m

h = 22 cm

<h3>Height of oil column</h3>

Oil is less dense than water and will float on water.

Height of oil column = 22 cm - 20 cm = 2 cm

Learn more about density here: brainly.com/question/6838128

#SPJ1

7 0
2 years ago
Jane, looking for tarzan, is running at top speed (5.2 m/s) and grabs a vine hanging 4.5 m vertically from a tall tree in the ju
kumpel [21]
While Jane is running has a kinetic energy, which is Ek = 1/2*m*v^2 where m is mass and v is velocity  When she grabs a vine, she is going to change the kinetic energy to potential energy.  
We know that potential energy is given by Ep = m*g*h where m is mass, g is gravity constant and h is height  
So while running the kinetic energy is Ek = 1/2 * m * 5.2^2 = 13.52*m 
Then all that energy is used to swing upward and gain potential energy 
Ep = m*g*h = Ek = 13.52*m  
m*9.8*h = 13.52*m 
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8 0
2 years ago
Chứng minh V=kq/r từ mối liên hệ giữ E và V
Marat540 [252]

Answer:V=Aq=KQr

Explanation:

Không biết V bạn kí hiệu ở đây là gì nhỉ? Có phải là điện thế?

Điện thế tại 1 điểm trong điện trường được định nghĩa là công làm vật dịch chuyển từ vị trí đó đến vô cùng. V = A/q

Chứng minh thì được, nhưng chỉ e bạn không có hiểu biết về nguyên hàm, tích phân nên không hiểu.

- Xét tại vị trí cách điện tích Q một đoạn x, khi đó điện tích q sẽ chịu 1 lực: dF=KQ.qx2

Điện tích q dịch chuyển 1 khoảng dx rất nhỏ. Khi đó công do lực điện trường gây ra là:

dA=dF.dx=KQ.qx2dx

Công để dịch chuyển điện tích q từ vị trí r đến vô cùng là:

A=∫∞rdA=∫∞rKQ.qx2dx=KQ.qr−KQ.q∞=KQ.qr

Theo đúng định nghĩa: V=Aq=KQr

4 0
3 years ago
A car traveling at 15 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration ?
Nataliya [291]

Answer:

-3m {s}^{-2}

Explanation:

The initial velocity, u, of the car=15m/s

The final velocity, v, of the car =0m/s

Time, t, taken for the car to come to a stop=5s

Acceleration is calculated by,

a= \frac{v - u}{t}

By substitution,

a= \frac{0- 15}{5}

a= \frac{- 15}{5}

a = -3 {ms}^{ - 2}

The negative sign implies that the car has decelerated.

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