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Nataly_w [17]
2 years ago
15

A bag of sand has a density of 45 g/cm3 and a mass of 15 kg. How much space does the sand take up?

Physics
2 answers:
mamaluj [8]2 years ago
6 0

Answer:

Volume of the sand bag, V=333. 33 cm^3

Explanation:

Given that,

Density of sand bag, d=45\ g/cm^3

Mass of the sand bag, m = 15 kg = 15000 kg

We need to find the space taken by the sand bag. The occupied space is called the volume of the sand bag. Density is given by :

d=\dfrac{m}{V}

V=\dfrac{m}{d}

V=\dfrac{15000\ g}{45\ g/cm^3}

V=333.33\ cm^3

or

V=333.33\ cm^3

So, the volume of the sand bag is V=333.33\ cm^3. Hence, this is the required solution.

Aleks [24]2 years ago
3 0

Volume = mass/density

 

Volume = 15000 g/45 g/cm3 ≈ 333.3 cm<span>3</span>

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Answer:

Explanation:

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We shall apply law of conservation of angular momentum .

initial total angular momentum

I x ω₀ - 4I x ω₀ = - 3Iω₀

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total final angular momentum = ( I + 4I ) ω

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ω = - 3 / 5 ω₀ .

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Initial total rotational K E

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= 1/2 x 9 / 5 I ω₀²

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=( .9 - 2.5 )I ω₀²

= - 1.6 I ω₀² Ans

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a vector a has components a x equals -5.00 m in a y equals 9.00 meters find the magnitude and the direction of the vector
Murrr4er [49]

Answer:

The magnitude = 10.30 m

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Explanation:

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\bar A  = \sqrt{A_x^2 + A_y^2}

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\bar A  = \sqrt{25 + 81}

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tan \theta  = \frac{5}{9}

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